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dusya [7]
3 years ago
7

X/3+9=17 simplify your answer

Mathematics
1 answer:
frosja888 [35]3 years ago
8 0
I think the answer might be x=24
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A child building a tower with Blocks uses 15 for the bottom row. Each row has 2 fewer blocks than the previous row. What formula
xenn [34]

Answer:

B)blocks in 5th row=15+(5-1)(-2)

Step-by-step explanation:

We are given that

Number of block in bottom row=15

Each row has 2 fewer blocks than the previous row

We have to find the formula would you use to find the number of blocks in the 5th row.

Number of blocks in  second row=15-2=15+1(-2)

Number of blocks in third row=15-2-2=15+2(-2)

Number of blocks in 4th row=15-2-2-2=15+3(-2)

Number of blocks in 5th row=15-2-2-2-2=15+4(-2)

Therefore, number of block in 5th row

15+(5-1)(-2)

This is required formula to find the number of blocks in the 5th row

Hence, option B is true.

B)blocks in 5th row=15+(5-1)(-2)

4 0
3 years ago
If f={(0,2),(2,6),(3,5),(4,9)} what is f^(-1)(9)
tangare [24]

Answer is 9 f-^1

I hope this correct :D

7 0
3 years ago
A circle has a radius of five ft.
Flura [38]
A. for the circumference it is C=pi(d)=pi(2r)=pi(10)=  31.4 ft
b. for the area it is A=pi(r)^2=pi(5)^2=pi(25)= 78.5 ft squared
c. since the are is 78.5 ft squared multiply by $4.50= $353.25 to floor the circle.
6 0
3 years ago
How would I find X? I tried using a2 + b2 =c2 but nothing worked
kozerog [31]
Can you please explain this a bit better? i dont understand
3 0
3 years ago
How many three letter permutations can be formed from the first five letters of the alphabet?
Vsevolod [243]

Answer:

There are 60 permutations that can be formed from the first five letters of the alphabet.

Step-by-step explanation:

The number of three letter permutations that can be formed from the first five letters of the alphabet is 5P_{3}.

5P_{3} =\frac{5!}{(5-3)!}

=\frac{5!}{2!}

= 60

Hence, there are 60 permutations that can be formed from the first five letters of the alphabet.

6 0
3 years ago
Read 2 more answers
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