The graph gives no reason to expect that y=0 is excluded, so we conclude the range is ...
... y ≥ 0
Answer:
Using the quadratic formula to solve 5x = 6x^2 – 3, what are the values of x?
5x = 6x^2 – 3
Subtract 5x from both sides:
0 = 6x^2 – 5x – 3
a = 6, b = -5, c = -3
x = (-b ± √(b^2 - 4ac))/(2a)
x = (-(-5) ± √((-5)^2 - 4(6)(-3)))/(2(6))
x = (5 ± √(25 + 72))/12
x = (5 ± √(97))/12
Step-by-step explanation:
Answer:
Step-by-step explanation:
The given polynomial is :
p(x) = 5-10x
We need to find the zeros of the above polynomial. To find it, put p(x) = 0
5-10x = 0
Subtract 5 from both sides
5-10x-5=0-5
-10x=-5
or
10x=5
Divide both sides by 10.
x = 0.5 = 1/2
Hence, the zeros of the polynomial is 1/2.
