The point-slope equation of a line that cointains the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so
point (-2,3) and slope -4
y-3=-4(x-(-2))
y-3=-4(x+2) is da equation
Answer:
x ≈ 78.7° (in degree)
x ≈ 1.4 (in radians)
Step-by-step explanation:
Given in the question an equation
tan(x) = 5
x = 
x = 78.69
x ≈ 78.7°
In radian:
x ≈ 1.4
This work is faster rate than grading 36 assignments in 30 minutes because :
25 ÷ 20 = 1.25
1.25 hw assignment per minute
36 ÷ 30 = 1.2
1.2 hw assignments per minute
Answer:
9
Step-by-step explanation:
It is congruent to the other side.
Answer:
1. A = 59
2. A = 43
Step-by-step explanation:
If we have a right triangle we can use sin, cos and tan.
sin = opp/ hypotenuse
cos= adjacent/ hypotenuse
tan = opposite/ adjacent
For the first problem, we know the opposite and adjacent sides to angle A
tan A = opposite/ adjacent
tan A = 8.8 / 5.2
Take the inverse of each side
tan ^-1 tan A = tan ^-1 (8.8/5.2)
A = 59.42077313
To the nearest degree
A = 59 degrees
For the second problem, we know the adjacent side and the hypotenuse to angle A
cos A = adjacent/hypotenuse
cos A = 15.3/21
Take the inverse of each side
cos ^-1 cos A = cos ^-1 (15.3/21)
A = 43.23323481
To the nearest degree
A = 43 degrees