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2 years ago

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Mathematics

2 answers:

saveliy_v [14]2 years ago

6 0

Answer:

Step-by-step explanation:

ludmilkaskok [199]2 years ago

5 0

Answer:

1,639,872,000 seconds

Step-by-step explanation:

your answer is c

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Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

The estimate is $- 0.0265\le K \le 0.0465$

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

2 years ago

7. Write an equation for the line that is parallel to the given line and that passes through the given point.

Vlad1618 [11]

Answer:

C. y = 1/2x - 14

Step-by-step explanation:

Find the slope of the original line and use the point-slope formula y − y 1 = m ( x − x 1 ) to find the line parallel to y = 1 /2 x − 8 .

y = 1 /2 x − 14 PARALLEL

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Find the negative reciprocal of the slope of the original line and use the point-slope formula y − y 1 = m ( x − x 1 ) to find the line perpendicular to y = 1 /2 x − 8 .

y = − 2 x − 29 PERPENDICULAR

8 0

2 years ago

The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?

Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are $(x_{1}, y_1)$ and $(x_2, y_2)$ then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be: