Answer:
0
Explanation:
This question involves a single gene coding for sight in humans. The allele for normal vision (C) is dominant over the allele for color blindness (c).
Based on the question, If Jennifer is normal (and is not a carrier) i.e. she has a genotype CC, and her husband, James, is colorblind with genotype cc. Each parent will produce C and c gametes respectively. Using these gametes in a punnet square (see attached image), all of the offsprings will have the genotype Cc, which is phenotypically normal visioned.
Therefore, according to this question, the chance of their daughter being color blind is 0.
