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alekssr [168]
3 years ago
8

Hi can someone plz help me ty btw happy holidays

Mathematics
2 answers:
Colt1911 [192]3 years ago
8 0

Answer:

She will have 16 begonia plants the fourth year.

Step-by-step explanation:

0   1   2   3   4

1    3   9  27  81

Please mark brainliest

Vika [28.1K]3 years ago
3 0

Answer:

Happy holidays to you too!

add two to the rest so

year one- 3

year two-5

year three-7

year four-9

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Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

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  • Symmetry: For all x,y, if xRy then yRx.
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Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

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3 years ago
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luda_lava [24]

Answer:

Step-by-step explanation:

3 0
2 years ago
14 less than a number all divided by the same number
Fynjy0 [20]

Answer:

(n-14) / n

Step-by-step explanation:

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"14 less" means "subtract 14", --> we have (n-14);

now we need to divide (n-14) by same number as your number, which is "n"---> final expression is:  (n-14)/n

6 0
3 years ago
I really need someone to help me out
elixir [45]

All it takes for a relation to be a function is for each possible first number of a pair there's only one possible second number.


So if any of the sets has two pairs with the same first number, that one's not a function.


The last one has (3,2) and (3,5) so isn't a function.



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4 years ago
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