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alekssr [168]
2 years ago
8

Hi can someone plz help me ty btw happy holidays

Mathematics
2 answers:
Colt1911 [192]2 years ago
8 0

Answer:

She will have 16 begonia plants the fourth year.

Step-by-step explanation:

0   1   2   3   4

1    3   9  27  81

Please mark brainliest

Vika [28.1K]2 years ago
3 0

Answer:

Happy holidays to you too!

add two to the rest so

year one- 3

year two-5

year three-7

year four-9

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Simplify<br><br> a+a+a=<br> 4b-b<br> 3x2+x2
Reika [66]
<h2>Good morning,</h2>

<em><u>__________________</u></em>

<em><u>Answer</u></em>:

a+a+a = 3a.

4b-b = 3b.

3x²+x² = 4x².

<u><em>explanation</em></u>

a+a+a = 3a.

4b-b = b(4 - 1) = b × 3 = 3b.

3x²+x² = x²(3 + 1) = x² × 4 = 4x².

_______________________________

:)

7 0
3 years ago
I need some serious help on this
motikmotik
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4 0
3 years ago
What expressions are equivalent to -2.5 (1 - 2n) - 1.5n?
jok3333 [9.3K]

Answer:

C. -2.5 - 6.5n

Step-by-step explanation:

i just think thats the answer

8 0
3 years ago
Read 2 more answers
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
Stella works for a company that makes aluminum cans. A large soup can have a radius of 8 centimeters and a height of 20 centimet
4vir4ik [10]
Could possibly be 36
6 0
3 years ago
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