Answer:
The data we have is:
The acceleration is 3.2 m/s^2 for 14 seconds
Initial velocity = 5.1 m/s
initial position = 0m
Then:
A(t) = 3.2m/s^2
To have the velocity, we integrate over time, and the constant of integration will be equal to the initial velocity.
V(t) = (3.2m/s^2)*t + 5.1 m/s
To have the position equation, we integrate again over time, and now the constant of integration will be the initial position (that is zero)
P(t) = (1/2)*(3.2 m/s^2)*t^2 + 5.1m/s*t
Now, the final position refers to the position when the car stops accelerating, this is at t = 14s.
P(14s) = (1/2)*(3.2 m/s^2)*(14s)^2 + 5.1m/s*14s = 385m
So the final position is 385 meters ahead the initial position.
Answer:
DEH and HEJ are complementary angles for example.
Step-by-step explanation:
We need to provide any 2 angles that sum to 90deg. We can clearly see that DEH and HEJ are complementary, we can see the same for JEK and KEF.
I don't believe there's more.
No, because any real valued term with degree 0 would be a constant. All constants in an expression can be combined into single term. Therefore if the expression were of degree 0, all the terms would be constants and could be combined into a single term making the expression a monomial.
2x * 3x = 6x^2
2x * (-4) = 8x
7 * 3x = 21x
7 * (-4) = -28
6x^2 + 29x - 28
Answer:
7/12
Step-by-step explanation:
total: 12 roses
white roses: 5
pink roses: 7
fraction of pink roses = 7/12
