Answer:
68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
Step-by-step explanation:
The lengths of a lawn mower part are approximately normally distributed

Standard deviation =
We are supposed to find What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)
Formula : 
At x = 3.8

Z=-1
Refer the z table for p value
p value =0.1587
At x =4.2

Z=1
Refer the z table for p value
p value =0.8413
P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826
So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
The answer your looking for is D
Answer:
the answer is 288 because 72 would be one fourth or 25% of 288. 72 plus 72 plus 72 plus 72 equals 288 equals 100%
The picture in the attached figure
we know that
total amount of sap =[3*(1/4)+2*(3/8)+4*(5/8)+1*(1)]
total amount of sap =[(3/4)+(6/8)+(20/8)+(1)]
total amount of sap =[(3/4)+(3/4)+(10/4)+(4/4)]
total amount of sap =[20/4]
total amount of sap =5 gallons
total of trees=10
<span>[amount of sap collected from each tree]=total amount of sap/total of trees
</span>
[amount of sap collected from each tree]=5/10----> 0.5 gallons per tree
the answer is0.5 gallons