Question

Answer my math question I asked so many times I lost most of points by

Answer 1

Answer:

Step-by-step explanation:

Parabolas can be written in the form

$y = a(x-h)^2+k$

The vertex is (h, k). The vertex in the graph is (5, 0).

so far, we have

$y = a(x-5)^2+0\\y = a(x-5)^2$

The other points we are given are (6, 1), (7, 4), (8, 9)

$9 = a(8-5)^2\\9 = a(3)^2\\9 = 9a\\a = 1\\\\4 = a(7-5)^2\\4 = a(2)^2\\4 = 4a\\a = 1\\\\1 = a(6-5)^2\\a = 1$

In vertex form

$y = (x-5)^2\\y = x^2 - 10x + 25$