Answer:
50%
Explanation:
top left of square qould be Bb
Top right: Bb
Bottom left: bb
bottom right:bb
Haploid if i remember correctly
Here we can see that 7 phenotypes appeared in F2 generation, so the number of genes involved is 3 and alleles is 6. Contribution per allele = 4 cm Base contribution = 6 cm
Genotype of Harvey = aa bb cc Genotype of Erma = AA BB CC
Number of dominant alleles if length is
18 cm = 18-6 / 4 = 12 / 4 = 3.
F1 generation genotype = Aa Bb Cc This clarifies why the length is 18 cm, as there are three dominant alleles.
seven 1. It is likely that there are gene pairs in this cross. There are
categories of phenotypes. The genotypes of the parents would be combinations of alleles that would produce a 6 cm ( aabbcc ) tail and a 30 cm) tail, whereas the 18 cm offspring would have a genotype of AaBbcc.
learn more about phenotypes here: brainly.com/question/902712
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