Problem 13
10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get
10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q
so we get the original expression again. Here 10 is the GCF of the two terms.
--------------------------------------------------------------
Plug p = 1 and q = 2 into the factored form
10*(p+q) = 10*(1+2) = 10*(3) = 30
As a check, let's plug those p,q values into the original expression
10*p+10*q = 10*1+10*2 = 10+20 = 30
We get the same output of 30
Answer:
y = x² - 10x + 41
Step-by-step explanation:
The standard form of a quadratic is ax² + bx + c : a ≠ 0
Given
y = (x - 5)² + 16 ← expand (x - 5)²
= x² - 10x + 25 + 16
= x² - 10x + 41 ← in standard form
Answer:
The function that can be used in the online shopping club about its monthly revenue is:
Step-by-step explanation:
First, we're gonna take into account the different values we have in the exercise:
- 10,000 members
- $7 per month for membership
- Loses of 400 members by each $1 monthly increase
How the variable 
represents the price increase, we can do the formula below:
In this formula, we represent in the first part that by each 1 in the variable , the total of members will be reduced in 400, in the second part, we mention that at the same time, the membership fee will be increased in the same value of . Now we must simplify this function:
We operate the values:
Solve we can:
And organize:
At the end, how 
represents the monthly revenue received by the club, we use that variable for our formula:
Answer:
Step-by-step explanation:
