Answer:

Step-by-step explanation:
Hi there!
Slope-intercept form:
where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0)
<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>
where two points that fall on the line are
and 
On the graph, two points are highlighted for us: (0,-4) and (2,2). Plug these into the formula:

Therefore, the slope of the line is 3. Plug this into
:

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

Recall that the y-intercept occurs when x=0. Given the point (0,-4), the y-intercept is therefore -4. Plug this into
:

I hope this helps!
Answer:
1.5x=6
x=4
Step-by-step explanation:
The area is length times width so 1.5 times x is the correct equation. Make x equal to one by dividing both sides by 1.5. x=6/1.5. Simplify this to get x=4.
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(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when
and
, and because the velocity function is continuous, you need only check the sign of
for values on the intervals (0, 3) and (3, 6).
We have, for instance
and
, which means the particle is moving the positive direction for
, or the interval (3, 6).
(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

which follows from the definition of absolute value. In particular, if
is negative, then
.
The total distance traveled is then 4 ft.
(g) Acceleration is the rate of change of velocity, so
is the derivative of
:

Compute the acceleration at
seconds:

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)
Yes What do you need help with ?
Answer:
x = 4 or x = -3/2
Step-by-step explanation:
To simplify and solve this, let's use the quadratic formula.
So the format of a quadratic equation is supposed look like this:

Let's find a, b, c:
- a is the coefficient of x^2
- b is the coefficient of x
- c is the constant term
Now let's solve the equation.
Let's solve your equation step-by-step.
2x^2−5x−12=0
For this equation: a=2, b=-5, c=-12
2x^2+−5x+−12=0
Step 1: Use quadratic formula with a=2, b=-5, c=-12.



or 
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<u>Answer:</u>
x = 4 or x = -3/2