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e-lub [12.9K]
3 years ago
8

In 2011, Japan experienced an intense earthquake with a magnitude of 9.1 on the Richter scale. In 2003, Japan experienced anothe

r intense earthquake that measured 8.3 on the Richter scale. Compare the intensities of the two earthquakes. Use a logarithmic model to solve. Round to the nearest whole number.
Mathematics
2 answers:
zepelin [54]3 years ago
6 0

Answer:

The intensity of the 2011 earthquake was about 6 times the intensity of the 2003 earthquake.

Step-by-step explanation:

To compare the intensities, we first need to convert the magnitudes to intensities using the log formula. Then we will set up a ratio to compare the intensities.

Convert the magnitudes to intensities and write them in exponential form.

R=logI

2011 earthquake:

9.1I=logI=109.1

2003 earthquake:

8.3I=logI=108.3

Form a ratio of the intensities.

intensity for 2011intensity for 2003

Substitute in the values and divide by subtracting the exponents to find

109.1108.3100.8≈6.

The intensity of the 2011 earthquake was about 6 times the intensity of the 2003 earthquake.

Your answer:

The intensity of the 2011 earthquake was about 15 times the intensity of the 2003 earthquake.

Reika [66]3 years ago
3 0

Answer:

The intensity of the 2011 earthquake was about 6 times the intensity of the 2003 earthquake.

Step-by-step explanation:

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LUCKY_DIMON [66]

Answer:

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3 years ago
Help pls... 20 points
jok3333 [9.3K]
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If 9.8 - 5.29 is changed to 9.8 - 5.3=4.5, what must be done to 4.5 to get the exact answer for 9.8 - 5.29? Explain
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The answer is 4.51 and what needs to be added to 4.5 is a .01
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