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kow [346]
2 years ago
13

Graph the linear function w(x)=3/5x+2 All I need is the ordered pairs/points

Mathematics
1 answer:
Anastaziya [24]2 years ago
3 0

9514 1404 393

Answer:

  (0, 2), (5, 5)

Step-by-step explanation:

The w-intercept is the constant in the equation, so you know immediately that (x, w) = (0, 2) is one point on your graph.

Since the value of x is being multiplied by 3/5, it is convenient to choose an x-value that is a multiple of 5. When x=5, we have ...

  w(5) = (3/5)(5) +2 = 3+2 = 5

So, (x, w) = (5, 5) is another point on your graph.

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In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
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Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

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3 years ago
Paisley works on her drawings for 2 hours. She spends 1/6 hour on each drawing. How many drawings does she work on in 2 hours? H
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Answer:

1/12

Step-by-step explanation:

1/6 divided by 2 = 1/12

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