Answer:
where
denote arc lengths of two circles
Step-by-step explanation:
Let
denote arc lengths of two circles,
denote corresponding radii and
denote the corresponding central angles.
So,
and ![L=R\alpha _2](https://tex.z-dn.net/?f=L%3DR%5Calpha%20_2)
This implies
and ![\alpha _2=\frac{L}{R}](https://tex.z-dn.net/?f=%5Calpha%20_2%3D%5Cfrac%7BL%7D%7BR%7D)
As each circle has an arc where the measures of the corresponding central angles are the same, ![\alpha _1=\alpha _2](https://tex.z-dn.net/?f=%5Calpha%20_1%3D%5Calpha%20_2)
![\frac{l}{r}=\frac{L}{R}](https://tex.z-dn.net/?f=%5Cfrac%7Bl%7D%7Br%7D%3D%5Cfrac%7BL%7D%7BR%7D)
As radius of one circle is twice the radius of the other circle,
![R=2r](https://tex.z-dn.net/?f=R%3D2r)
![\frac{l}{r}=\frac{L}{2r}\\\frac{l}{1} =\frac{L}{2}\\L=2l](https://tex.z-dn.net/?f=%5Cfrac%7Bl%7D%7Br%7D%3D%5Cfrac%7BL%7D%7B2r%7D%5C%5C%5Cfrac%7Bl%7D%7B1%7D%20%3D%5Cfrac%7BL%7D%7B2%7D%5C%5CL%3D2l)
Given:
Consider the below figure attached with this question.
To find:
The perimeter of the polygon UVWXYZ.
Solution:
All sides and vertical and horizontal. So, we can easily find the side lengths of the given polygon by counting the boxes between two points.
From the figure it is clear that,
UV = 9 units
VW = 2 units
WX = 3 units
XY = 3 units
YZ = 6 units
ZU = 5 units
Now, perimeter is the sum of all the sides.
![Perimeter=UV+VW+WX+XY+YZ+ZU](https://tex.z-dn.net/?f=Perimeter%3DUV%2BVW%2BWX%2BXY%2BYZ%2BZU)
![Perimeter=9+2+3+3+6+5](https://tex.z-dn.net/?f=Perimeter%3D9%2B2%2B3%2B3%2B6%2B5)
![Perimeter=28](https://tex.z-dn.net/?f=Perimeter%3D28)
Therefore, the perimeter of UVWXYZ is 28 units.
1 foot = 12 inches. If you multiply 12 by 12 and then add 5, you get 149. 149 is less than 162 so it will be able to fit!
It seems that you have missed the necessary options for us to answer this question. But anyway, here is the answer. The method <span>of gathering data that is described by the statement "these are run only when probabilities are known as fact" is called SIMULATION. Hope this answers your question.</span>
I believe the correct answer is D Aarron Burr