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2 years ago

Plz help! The product of three consecutive natural numbers is 336. What are those numbers?

Mathematics

1 answer:

bekas [8.4K]2 years ago

8 0

Answer:

2x2x2x2x3x7,This is because all of that sum equals the total of

Step-by-step explanation:

2x2x2x2x3x7

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Answer:

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2 years ago

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Can someone explain, i'm literally sweating trying to figure it out

ASHA 777 [7]

Answer:

54 degrees.

Step-by-step explanation:

So a fun fact is that the exterior angle is equal to the sum of the opposite two interior angles (at least within triangles).

Given this, set these values equal to each other to get the value of a.

d = a + b

2a = (a+10)+44

2a = a + 54

a = 54

The measure of the exterior angle is 54 degrees.

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2 years ago

What is the radius and diameter of the following circle?

prisoha [69]

Answer:

Radius = 6.5cm

Diameter = 13cm (given)

Step-by-step explanation:

The diameter is the length of one side of a circle to the other. It's already given in the diagram as 13cm.

The radius is half of the diameter. 13 divided by 2 is 6.5cm.

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2 years ago

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(9x2 + 8x) – (2x2 + 3x)

Arte-miy333 [17]

Answer: 14+5x

Step-by-step explanation:

(18+8x) - (4+3x)

18+8x-4-3x

14+5x

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3 years ago

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Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

Plz help! The product of three consecutive natural numbers is 336. What are those numbers?​

Plz help! The product of three consecutive natural numbers is 336. What are those numbers?