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3 years ago

the function y=3.28x converts length from x meters to y feet Im really stuck im not real sure what to do

1 answer:

7 0

Step-by-step explanation: So this one can be a little confusing, but I think I can help. You see if 'y'= number of feet and 'x'= number of meters then y=3.28x is a way for you to figure out how many feet are constant to every meter.

Look at it more like, Number of Feet= 3.28 times the number of meters.

If you want to figure out many feet are constant to let's say...2 meters, then you would replace the 'x' variable with 2 and multiply it by 3.28.

It would look something like this:

y=3.28(2)

y= 6.56

Thus, every 1 feet there are 6.56 meters, or 6.56 meters equals 1 foot.

Hope this helps a little, tell me if you need anymore help with this!

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Pitágoras filósofo matemático griego biblio entre los años 500 8496 antes de Cristo A qué edad murió y cuántos años hace que mur

Maurinko [17]

Answer:

if you can transfer to englis i may be able to help

Step-by-step explanation:

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3 years ago

Does this graph show a function explain how you know

Semenov [28]

The correct option is Option D: Yes, the graph passes the vertical line test.

The function is a relationship between two distinct sets X and set Y which can be many-one or one-one. here set X is called the domain and set Y is called the codomain.

The vertical line test states that

If we draw a straight vertical line( which is also parallel to the y-axis) and it touches the graph at only one point at all locations, then that relation is said to be a function and this relation will be also one-one.

So here in this function shown in the graph.

If we draw a vertical line parallel to the y-axis in this at any location then it crosses the graph only once. So, it passes vertical line test. And this graph is a function. Therefore option D is correct.

Learn more about function

here: brainly.com/question/17043948

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3 0

2 years ago

Can someone make sure the first 3 questions are correct and help me on the 4th one?

Ratling [72]

Sorry, I'm no help because I have no idea how to do those!

4 0

3 years ago

Whats the cost of each vegetable if 5 squash and 2 zucchini is $1.32

alex41 [277]

Answer:

Step-by-step explanation:

We first need to define a couple of variables. Let s = the cost of 1 squash and z = the cost of 1 zucchini.

Now lets translate the words into algebra:

"The cost of 5 squash and 2 zucchini is $1.32" ===> 5s + 2z = 1.32

"Three squash and 1 zucchini cost $0.75" ===> 3s + z = 0.75

There are several ways to solve systems of equations. Let's use substitution. We can find what z equals in terms of s by manipulating the second equation:

3s + z = 0.75

-3s -3s

------------ -------------

z = -3s +0.75

Now lets substitute (-3s + 0.75) into the first equation for z, then solve for s:

5s + 2(-3s + 0.75) = 1.32

Can you handle it from here?

(Hint: Once you have solved for s, you can substitute that value back into either of the equations and solve for z.)

3 0

3 years ago

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .

Equate the right-hand side of these two equations:

$0.810\, x \approx 0.649\, (x + 20)$ .

Solve for $x$ :

$x \approx 81\; \rm ft$ .

Hence, the height of the top of this tree relative to the base of the hill would be $(x + 20)\; {\rm ft}\approx 101\; \rm ft$ .

6 0

3 years ago