Answer:
x=2 , y = 1
Step-by-step explanation:
x + 2(2x-3) = 4
x+4x-6=4
5x-6=4
5x= 10
x=10/5
x=2
subs x=2 into x +2y=4
2+2y=4
2y=2
y=2/2
y=1
Answer:
{-8, -7, 0, 6, 9}
Step-by-step explanation:
1. The range of a relation is the set of its possible output values, also known as the y-values of a function.
2. Let's find the y-coordinate of each point.
3. Now, let's order them (from least to greatest) to get the range.
- {-8, -7, 0, 6, 9}
Therefore, the range of this relation is {-8, -7, 0, 6, 9}.
Given: ax-by>c
Subtract ax on both sides: -by>-ax+c
Divide both sides by -b: y<(-ax+c)/-b
Simplify: y<(ax-c)/b
your answer: y<(ax-c)/b
Answer:
0.1
Step-by-step explanation:
"h and k cannot both equal zero" -- yes, it can. if the vertex of a parabola is at (0, 0), there's nothing incorrect/invalid about that!!
"k and c have the same value" -- k and c do not have the same value. "k" is the y-value of the vertex and c is the constant in your quadratic equation, and the constant is not necessarily the y-value.
"the value of a remains the same" -- this is true. the a's in your equations are the same values, because the a-value is the coefficient of the x-variable in both equations. y = a(x - h)^2 and y = ax^2 -- both of these have a applying to your x-variables.
"h is equal to one half -b" -- this isn't true. the formula for calculating the x value of the vertex (h is the x-value of the vertex) is h = (-b/2a). -b/2a is not the same as one half -b because this answer choice doesn't involve the a-value.