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maks197457 [2]
3 years ago
13

HELP!!! EMERGENCY!!! How many solutions does the following equation have? PLEASE SHOW WORK!

Mathematics
1 answer:
V125BC [204]3 years ago
7 0
The answer is B) no solution
You might be interested in
What's 2/5 - 9/10 as a fraction?
elena-s [515]

Answer:

- 1/2

Step-by-step explanation:

turn 2/5 to have the same denominator as 10

2 ( 2 ) = 4

5 ( 2 ) = 10

4/10 - 9/10

= -5/10

simplify

-5/10 = -1/2

hope this helps

4 0
2 years ago
Find the slope of the line passing through (-9,3), (-3,-5)
egoroff_w [7]

Answer:

-4/3

Step-by-step explanation:

Slope: (y2-y1)/(x2-x1)

(-5-3)/(-3+9) = -8/6 = -4/3

The slope is -4/3

6 0
3 years ago
What is the surface area of a cylinder that has the following measurements? area of each base: 50.24 ft2 area of lateral surface
irinina [24]

Answer:

TSA = 175.84 ft²

Step-by-step explanation:

We are given;

Lateral surface area; A_L = 75.36 ft²

Area of base; A_b = 50.24 ft²

Height of cylinder; h = 3ft

Formula for total surface area of Cylinder is;

TSA = 2πr² + 2πrh

Now, lateral surface area is given by the formula; A_L = 2πrh

Area of base is given by the formula;

A_b = πr²

Thus, let's apply these 2 formulas to the formula for total surface area;

TSA = 2(Area of base) + Lateral surface area

TSA = (2 * 50.24) + 75.36

TSA = 175.84 ft²

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
2 years ago
You estimate that a baby pig weighs 20 pounds. The actual weight of the baby pig is 16 pounds. Find the percent error.
WARRIOR [948]
20-16=4
16/4=4
1/4=.25
.25=25%
5 0
3 years ago
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