We know that
<span>Out of 120 students----------> 34 chose orange as the favorite fruit
</span>Find the <span>percentage
</span><span>percentage=34/120------> 17/60-----> 0.2833------> 28.33%
for </span>2,000 students
0.2833*2000=566.67-----------> about 567 students
the answer is
about 567 students
First you have to find out how much one cost.
In order to do that you have to divide 3.60/6. You would get 6. That is how much one cost. Then you have to multiply 6*2 and you would 12. So the answer is $12. I hope this helps
Step-by-step explanation:
(x+2y)(x-2y)
- x^2-2xy+2xy-(2y)^2
- x^2-4y^2
Answer:
The randomization distribution is created under the assumption that H₀: p = 0.1
The randomization distribution will also be centred at 0.1
Step-by-step explanation:
If the distribution was truly random, 1 out of 10 students will choose math as his/her favorite subject.
This means that the randomization will have the null hypothesis saying that the proportion of students who will choose maths as their favourite subject = 0.1
Mathematically, it'll be written as
The null hypothesis is given as
H₀: p = 0.1
And the randomization distribution will be centred at 0.1 too.
The alternative hypothesis will now prove the theory they're looking to see in the question that
Hₐ: p < 0.1
Hope this Helps!!!
Answer:
43.6 * 2.94 = 436/10 * 294/100 = (436 * 294)/1000 = 128184/1000 = 128.184
