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zhannawk [14.2K]
2 years ago
7

The equation (x + 6)^2 + (y + 4)^2 = 36 models the position and range of the source of a radio signal. Describe the position of

the source and the range of the signals
Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
7 0

Answer:

position: (-6, -4)

range: 6

Step-by-step explanation:

The equation is that of a circle centered at (-6, -4) with a radius of √36 = 6. We presume that the "position" is that of the circle's center, and the "range" is the radius of the circle.

___

The standard form equation of a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

Matching parts of the equation, we find ...

h = -6, k = -4, r = √36 = 6.

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Which of the following is 2/11 closest to?<br> 0.<br> 1/2.<br> 1.
VLD [36.1K]

2/11 is 0.181818 as a decimal so closest to 0.

4 0
2 years ago
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Please solve for x. I need this answered.
spin [16.1K]

2.5x - 3 + 2x = 1.75x - 1.25x + 13

4.5x - 3 = 0.50x + 13

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x = 4

Answer: 4

2. We'll assume those xs are in the numerator

(3/7)x - 1/4 + (3/7)x = (9/7)x - (3/7)x + 3/4 - 1

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8 0
3 years ago
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Help on math please!
DedPeter [7]
(13•4) + (3•8) +3 = 79
The total cost is $79
6 0
3 years ago
There are seven cats in my neighborhood, with an average of $41$ whiskers each. If one of the cats has $17$ whiskers, how many w
harkovskaia [24]

Answer:

Each of the other cats have 45 whiskers on average.

Step-by-step explanation:

Let x represent the average number of whisker of each cat.

We have been given that there are 7 cats in my neighborhood, with an average of 41 whiskers each.

The total number of whiskers of six cats would be 6x.

Since one of the cats has 17 whiskers, so the total number of whiskers of 7 cats would be 6x+17

We will use average formula to solve our given problem.

\text{Average}=\frac{\text{Sum of data points}}{\text{Number of data points}}

Upon substituting our given values, we will get:

41=\frac{6x+17}{7}

Let us solve for x.

41*7=\frac{6x+17}{7}*7

287=6x+17

287-17=6x+17-17

270=6x

Switch sides:

6x=270

\frac{6x}{6}=\frac{270}{6}

x=45

Therefore, the each of the other cats have 45 whiskers on average.

8 0
3 years ago
PLEASE HELP!!!!!!!!
vfiekz [6]

Answer:

about 78 years

Step-by-step explanation:

Population

y =ab^t  where a is the initial population and b is 1+the percent of increase  

    t is in years

y = 2000000(1+.04)^t

y = 2000000(1.04)^t

Food

y = a+bt   where a is the initial population and b is constant increase

    t is in years

b = .5 million = 500000

y = 4000000 +500000t

We need to set these equal and solve for t to determine when food shortage will occur

2000000(1.04)^t= 4000000 +500000t

Using graphing technology, (see attached graph  The y axis is in millions of years), where these two lines intersect is the year where food shortages start.

t≈78 years

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3 years ago
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