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Natalka [10]
3 years ago
5

When I checked my bank account this morning I had $4,300. This is a relief

Mathematics
1 answer:
Ivan3 years ago
3 0

Answer:

ahaha that's good

you didn't steal right?

haha jk

lucky you!

You might be interested in
The measures of two complementary angles are 12q-9 and 8q+14 . Find the measures of the angles.
Lostsunrise [7]

Answer:

4.25

Step-by-step explanation: 12q - 9 ) + ( 8q + 14 ) = 90

Combine like Terms: 20q + 5 = 90

Subtract 5 from both sides: 20q = 85

Divide both sides by 20: q=4*(1/4)

So your angle is 4(1/4) or 4.25 degrees

8 0
3 years ago
Is the equation true,false, or open? 14+7+(-1)=21
yuradex [85]

Answer:

The Equation is False.

Step-by-step explanation:

(14+7)=21 + (-1) = 20

6 0
3 years ago
Read 2 more answers
F(x) =5x^2-20x+3 how to find minimum
Leya [2.2K]

Answer:

(2,-17) should be the minimum.

Step-by-step explanation:

The minimum of a quadratic function occurs at x=-\frac{b}{2a} . If a is positive, the minimum value of the function is f(-\frac{b}{2a})

f_{min}x=ax^2+bx+c occurs at x=-\frac{b}{2a}

Find the value of x=-\frac{b}{2a}

x = 2

evaluate f(2).

replace the variable x with 2 in the expression.

f(2)=5(2)^2-20(2)+3

simplify the result.

f(2)=5(4)-20(2)+3

f(2)=20-40+3

f(2)=-17

The final answer is -17

Use the x and y values to find where the minimum occurs.

HOPE THIS HELPS!

3 0
3 years ago
Help please I’m stuck
Jlenok [28]
12:4=3
9:3=3
so u multiply each side by 3 to get the second triangle..
answer: 4.5*3 =13.5
4 0
3 years ago
Read 2 more answers
Write an equation for the line in point slope form through the points (2, −6) and (−1, −8).
igomit [66]

Let point A be (2, -6) and point B (-1, -8)

m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-8 - (-6)}{-1 - 2} = \frac{-8 + 6}{-1 -2} = \frac{-2}{-3} = \frac{2}{3}

Use the point-slope formula and whichever point you want as , in this case I'll use

y - y_1 = m(x - x_1)\\y - (-6) = \frac{2}{3}(x - 2)\\y + 6 = \frac{2}{3}x - \frac{4}{3}\\y = \frac{2}{3}x - \frac{4}{3} - 6\\y = \frac{2}{3}x - \frac{14}{3}

8 0
3 years ago
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