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Iteru [2.4K]
2 years ago
10

Which represents a total cost of 3 dance tickets at a price of c for each, less a one-time $2 discount?

Mathematics
1 answer:
Effectus [21]2 years ago
8 0

The equation that models the given statement is 3c - $2

<h3>Writing an Equation</h3>

From the question, we are to write the equation that models the given statement

The given statement is

"<em>total cost of 3 dance tickets at a price of c for each, less a one-time $2 discount</em>"

"the price of 3 dance tickets at a price if c for each" can be expressed as

3c

Thus,

Total cost of 3 dance tickets at a price of c for each, less a one-time $2 discount is

3c - $2

Hence, the equation that models the given statement is 3c - $2

Learn more on Writing equations here: brainly.com/question/22049822

#SPJ1

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riadik2000 [5.3K]

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[-4, infinity)

Step-by-step explanation:

the smallest possibly for a is -2 and if you add 2 to 12 you get b=14 so the smallest out can be is 14 and it can be any number higher because it with still be greater

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4 years ago
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bezimeni [28]

Answer:

x^6 + 2 x^5 - 6 x^4 + 3 x^2 + 6 x - 18

Step-by-step explanation:

f(x) = x^2 +2x-6

g(x) =x^4+3

We want to find f*g

(f*g)(x) = (x^2 +2x-6)(x^4+3)

Distribute

          =x^2*x^4 +3x^2 +2x*x^4 +2x*3 +-6x^4 -6*3

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Combine like terms

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8 0
4 years ago
Seven members of a Girl Scout troop report the following individual earnings from their sale of candy: $4, $1, $7, $6, $8, $2, a
Radda [10]

Answer:

(B) the mean is less than the mode and less than the median.

Step-by-step explanation:

Mean, Median, Mode is used to calculate the central tendency of the distribution.

Mean is defined as,

Mean = \dfrac{Sum of all observation}{Total number of observation}\\ \ \ \ \ \ \ \ \ = \dfrac{4+1+7+6+8+2+7}{7}

∴ Mean = 5

Median is the middle observation of the distribution after arranging it in ascending or descending order.

So, arranging distribution in ascending order we get,

$1, $2, $4, $6, $7, $7, $8

Also, a number of observation is 7 which is an odd number.

Hence, Median = (\frac{Number of observation + 1}{2})^{th} term

⇒ Median = (\frac{7 + 1}{2})^{th} term

⇒ Median = 4th term = 6

Mode is the observation which has highest frequency.

Here, only $7 is repeated 2 times.

Hence, Mode = 7.

Hence, we see that Mean < Median < Mode

So, Option (B) is correct i.e. mean is less than the mode and less than the median.

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