Answer:
SELECT product_name, amount_due, amount_paid,
cancelled, amount_refunded
FROM products
ORDER BY product_name ASC;
Explanation:
SQL (Structured Query Language ) was used above.
The SELECT command is used to list all the variables we want in our output.
The FROM command signifies the location.
ORDER BY command ensures that your result is ordered
ASC means Ascending Order.
; signifies the end of the query.
NOTE: Underscores were used because variables cannot be written with spaces between them
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
The answer is proxy server
A proxy server acts as an immediate or a gateway between you, the proxy client (example, the browser) and the internet or the destination website that you want to visit. Proxy servers are designed to re-route traffic and obscure source and destination. For instance, if you want to request a page like brainly, a proxy server will be able to retrieve this page for you by providing only its IP address to the site and act as a mediator between clients and the requested server. This however, does not mean that there is no link between you and this website. It means that all the information along with the requests you made will be collected by the proxy server.
I cants see the "Selected Road" And I cant answer this unless you put that up. Sorry.
Answer:
for cutting it's scissors for measuring it's the tiny measurement spoonlikes for mixing it's the blender and preparatory