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boyakko [2]
3 years ago
14

Solve the following system of equations by substitution

Mathematics
2 answers:
denis23 [38]3 years ago
5 0

Answer:

x = -3, y = -1

Step-by-step explanation:

In order to solve an equation using substitution you need to make one of the variables values opposite of one another. For example, 4's opposite would be -4. Moving on, we multiply the bottom equation by -2. That gives us y = -2x -4. We combine like values and the remaing equation is y = -1. Finally, we can insert our value;-1 = x +2. We do inverse operations and we are left with x = -3.

WITCHER [35]3 years ago
3 0

Answer:

(-1, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 2x + 3

y = x + 2

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                                                                                                  2x + 3 = x + 2
  2. [Subtraction Property of Equality] Subtract <em>x</em> on both sides:                         x + 3 = 2
  3. [Subtraction Property of Equality] Subtract 3 on both sides:                        x = -1

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Substitute in <em>x</em> [Original Equation]:                                                                  y = -1 + 2
  2. Add:                                                                                                                    y = 1
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OLga [1]

Answer:

-22+27i

Step-by-step explanation:

i =  \sqrt{ - 1}  \\ (3 - 4i)( - 6 + i) \\  = (3 - 4 \sqrt{ - 1} )( - 6 +  \sqrt{ - 1} ) \\  = 3( - 6 +  \sqrt{ - 1)}  - 4 \sqrt{ - 1} ( - 6 +  \sqrt{ - 1} ) \\  =  - 18 + 3 \sqrt{ - 1}  + 24 \sqrt{ - 1}  - 4 \\  =  - 22 + 27 \sqrt{ - 1} \\ putting \:  \:  \:  \sqrt{ - 1 }  = i \\  =  - 22 + 27i

Hope it helps.

Don't forget to click the Brainliest button if you like my answer.

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3 years ago
Solve for c.<br><br> 3 − 7c − 20c = 7(–7c − 19) + 14c<br><br> c =
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Answer:

\boxed{c = -17}

Step-by-step explanation:

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Given a leading coefficient of 8, polynomial roots of 1 &amp; 2, and the known point on the graph (4,5). Write an equation that
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Given:

The leading coefficient of a polynomial is 8.

Polynomial roots are 1 and 2.

The graph passes through the point (4,5).

To find:

The 3rd root and the equation of the polynomial.

Solution:

The factor form of a polynomial is:

y=a(x-c_1)(x-c_2)...(x-c_n)

Where, a is a constant and c_1,c_2,...,c_n are the roots of the polynomial.

Polynomial roots are 1 and 2. So, (x-1) and (x-2) are the factors of the polynomial.

Let the third root of the polynomial by c, then (x-c) is a factor of the polynomial.

The leading coefficient of a polynomial is 8. So, a=8 and the equation of the polynomial is:

y=8(x-1)(x-2)(x-c)

The graph passes through the point (4,5). Putting x=4,y=5, we get

5=8(4-1)(4-2)(4-c)

5=8(3)(2)(4-c)

5=48(4-c)

Divide both sides by 48.

\dfrac{5}{48}=4-c

c=4-\dfrac{5}{48}

c=\dfrac{192-5}{48}

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Therefore, the 3rd root on the polynomial is \dfrac{187}{48}.

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3 years ago
Here is an equilateral triangle. The length of each side is units. A height is drawn. In an equilateral triangle, a line drawn f
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1. Height of the equilateral triangle is: √3 units

2. Area of the equilateral triangle = √3 units²

3. Area = √3/4 x², when each side is x.

<h3>What is an Equilateral Triangle?</h3>

A triangle that has all its three sides equal in length, is referred to as an equilateral triangle.

1. Given the each side measures 2 units, and h is the height, applying the Pythagorean theorem, we would have:

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2. Area of the equilateral triangle = 1/2bh = 1/2(2)(√3)

Area of the equilateral triangle = √3 units²

3. If x is the side length of the equilateral triangle, we would have:

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Area = 1/2bh = 1/2(x)(√3/2x) = √3/4 x²

Learn more about equilateral triangle on:

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