Question

The sum of 6 consecutive integers is 339.

Answer 1

Answer:

54, 55, 56, 57, 58, and 59 are the numbers

Step-by-step explanation:

Let's pretend that the first number is $n$.

We know that these numbers are consecutive, meaning each number is one more than the other.

This means that

$n + (n+1)+ (n+2)+ (n+3)+ (n+4)+ (n+5) = 339$, since each number is consecutive.

We can combine like terms to get $6n + 15 = 339$.

Now let's solve for n.

$6n + 15 - 15 = 339-15\\\\6n = 324\\\\n = 54$

So $n=54$. This means the other 5 digits will be one more than the next.

So 54, 55, 56, 57, 58, and 59.

Hope this helped!