Answer:
A. a separate schedule.
Explanation:
This is explained to be cash flow schedule or also cash flow statement. It is explained to be on out of the three financial statement which used generally to report for cash which been generated and how this money has been totally been spent within a period or interval which could be a week, month, quarter or even probably a year.
In the statement of cash flows, the cash flows are known to be generated from investing activities section while inclusion of receipts from the sale of investments. This is why in the stated 20 year payable bond, it is known to have been recorded in statement of cash flows in a separate schedule.
Answer:
<u>B. extended product line length</u>
Explanation:
- The product line is a pricing strategy refers to as the pricing line extension and its purpose is to attract new customers, who may or may not be familiar with the current standard product line.
- Thus It adds a higher quality to the current products, considered as trading and forward stretch. Various features include the price lining, bundle pricing, bait pricing, leader pricing.
- Supermarkets like Walmart and amazon can often apply stretch top product lines so s to often grade there products to ensure that all markets are covered as to gain the maximum interest from customers.
Answer:
present value 15.826 million
r = 10.42 % = IRR
Explanation:
The problem requires a long solution. I have to use microsoft word for the solution. and its so explanatory on it.
Answer:
b. $98,625.
Explanation:
Maintenance budget : $99,000
Assembly area: 43,000
Painting Area: 29,000
Maintenance budget allocated to assembly (M):

Administration budget : $79,00
Assembly employees: 150
Painting employees: 150
Administration budget allocated to assembly (A):

Therefore, the total amount of indirect factory expenses that should be allocated to the Assembly Department for the current period is:

Answer:
EV(1) = max(46.8, 44.4, 53.6) = 53.6m
Explanation:
Diagram is shown in the attached file
EV(5) =max(42, 48) = 48m
EV(6) =max(46, 50) = 50m
EV(2) =0.20(42) + 0.80(48) = 46.8m
EV(3) =0.20(22) + 0.80(50) = 44.4m
EV(4) =0.20(-20) + 0.80(72) = 53.6m
EV(1) =max(46.8, 44.4, 53.6) = 53.6m