You obtain the following estimates for an AR(2) model of some returns data
1 answer:
Answer:
AR(2) model is not stationary
Explanation:
Given model : Yt = 0.803yt-1 + 0.682yt-2 + ut ---- ( 1 )
ut = noise error process
Aim : Check estimated model for stationarity
<em>step 1 : </em>represent the estimated polynomial of the model ( where: ut ∪ N(o,б^2 ) rewrite equation 1
Yt - 0.803yt-1 - 0.682yt-2 = ut ------- ( 2 )
hence the polynomial can be represented as :
( 1 - 0.803B - 0.682B^2 )Yt = ut
Characteristic of the obtained polynomial can be represented as ;
1 - 0.803λ - 0.682λ^2 - 1 = 0
attached below is the remaining part of the solution
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Answer: Project X
Explanation:
The Payback period is the amount of time it would take for the cash inflows accruing from an investment to payoff the cost of the investment.
Project X has a constant cashflow of $24,000 for 3 years and a cost of $68,000 for the Payback period is;
= 68,000/24,000
= 2.83 years
Project Y has an uneven cash flow with a cost of $60,000. Payback is calculated as;
= Year before payback + Amount left to be paid/cashflow in year of payback
Year before payback = 4,000 + 26,000 + 26,000
= $56,000
This means that the third year is the year before payback.
60,000 - 56,000 = $4,000
Payback period = 3 + 4,000/20,000
= 3.2 years
Based on a Payback period of 3 years, only Project X should be chosen as it pays back in less than 3 years.
