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3 years ago

You obtain the following estimates for an AR(2) model of some returns data

Business

1 answer:

Sergio039 [100]3 years ago

4 0

Answer:

AR(2) model is not stationary

Explanation:

Given model : Yt = 0.803yt-1 + 0.682yt-2 + ut ---- ( 1 )

ut = noise error process

Aim : Check estimated model for stationarity

<em>step 1 : </em>represent the estimated polynomial of the model ( where: ut ∪ N(o,б^2 ) rewrite equation 1

Yt - 0.803yt-1 - 0.682yt-2 = ut ------- ( 2 )

hence the polynomial can be represented as :

( 1 - 0.803B - 0.682B^2 )Yt = ut

Characteristic of the obtained polynomial can be represented as ;

1 - 0.803λ - 0.682λ^2 - 1 = 0

attached below is the remaining part of the solution

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You are a manager for Herman Millera major manufacturer of office furniture. You recently hired an economist to work with engine

KIM [24]

Answer:

$4000 is the correct answer to the given question .

Explanation:

The marginal cost with compare to the labor can be written as

$MC\ = \frac{dQ}{dL} \\MC =\frac{d\ ( 2(K)1/2(L)1/2\ )}{dL} \\\\MC=\frac{\sqrt{K} }{\sqrt{L} }$

Here K=9 units putting this value in the previous equation we get

$MC\ = \frac{\sqrt{9} }{\sqrt{L} }$

$MC=\frac{3}{\sqrt{L} }$

We can find the value of labor by the given formula that are given below

$V *MC=\ W\\400\ *\frac{3}{\sqrt{L} }\ =120\\ L=10$

From the given question that are mention in question

Q = 2(K)1/2(L)1/2

Putting the value of K and L in the given equation we get

$Q\ =2 * \sqrt{9} \ * \sqrt{100} \\Q\ = 60$

So profit maximizing output is =$60 chairs as the chairs can be sold for the $400 each so = $60 * $400 *10=$24000 chairs

As the competitive wage of $120 for 100 units as well as the total of $8,000 on the 9 units of capital equipment

=$20000

Therefore profit-maximizing level of output =$24000-$20000=$4000

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Molly is getting ready to file her tax return. She works and has a savings account. What tax forms does she need?

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valentina_108 [34]

Answerthe answer is d

Explanation:

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Learn more about the CVP graph here:

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