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2 years ago

Help me please an image is attached

Mathematics

2 answers:

Lubov Fominskaja [6]2 years ago

8 0

Answer:

C. The graph has y-intercept - 2, not initial value - 2.

Step-by-step explanation:

Hope this helps

Mashutka [201]2 years ago

3 0

Answer:

its C

Step-by-step explanation:

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El -2,4 es un número entero✨ Gracias!!! ✨✨✨

Marizza181 [45]

Answer:2

Step-by-step explanation:

subtract

3 0

3 years ago

Hi everyone! I have a question!

Tju [1.3M]

Answer:

7π

Step-by-step explanation:

SO first find the area of the whole circle

which has a radius of 3

a=πr^2

So 3^2=9

9π

Now the two circles which are the same in area due to having the same radius

so if you plug in the 1 for radius the answer would just be π or 1π

now multiply that by 2 becuase there are 2 identical circles

π*2=2π

Now subtract

9π-2π=7π

3 0

3 years ago

Read 2 more answers

Round to the nearest tenth 3.2649

katovenus [111]

Answer:

3.3

Step-by-step explanation:

5 0

2 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Brrunno [24]

Answer:

Converges at -1

Step-by-step explanation:

The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.

We will make use of integral by parts to determine:

let:

$u=x$ $dv=e^(2x)\cdot{dx}$

$du=dx$ $v=2\cdot{e^(2x)}$

$\int\limits^a_b {u} \, dv = uv -\int\limits^a_b {v} \, du$

$\int\limits^a_b {x\cdot{e^2^x} \, dx =2xe^2^x- \int\limits^a_b {2e^2^x} \, dx$

$\int\limits^a_b {xe^2^x} \, dx = 2xe^2^x-2e^2^x-C$

We can therefore determine that if x tends to 0 the limit is -1

$\lim_{x \to \0} 2xe^2^x-2e^2^x=0-1=-1$

5 0

3 years ago

3 Which of these is equivalent to 4 81 64 44 12

jek_recluse [69]

The answer is 44. ! Your welcome

8 0

3 years ago

Help me please *an image is attached*

Help me please an image is attached