All categories

2 years ago

Plz do this, I’m so exhausted. Thxx

Mathematics

2 answers:

brilliants [131]2 years ago

3 0

Answer:

12) B --> x < 8/3

13) B --> x ≤ 1/6

Step-by-step explanation:

12) Solving inequalities is just like solving normal equations where you and add, subtract, multiply and divide sides by the same value. Keep in mind dividing or multiplying by a negative flips the sign:

x - 10 < 6 - 5x

Add 5x to both sides to combine the x terms:

x - 10 < 6 - 5x

+5x +5x

6x - 10 < 6

Add 10 to both sides to isolate the x term:

6x - 10 < 6

+10 +10

6x < 16

Now, divide by 6 on both sides:

x < 8/3, this is B

13) Simplify 2 - 4:

2-3(2x + 1) ≤ 6x(-2)

Distribute:

2 - 6x - 3 ≤ -12x

Add 12x to both sides and combine like terms:

6x - 1 ≤ 0

Add 1 to both sides:

6x ≤ 1

Divide by 6:

x ≤ 1/6, this is B

Anna [14]2 years ago

3 0

12. B

X- 10 < 6-5x

So I brought over the five x to be on the side where the x is and then I placed the others on the other side so…

5x + x < 6 + 10

6x < 16

Then I divided both sides by 6

You might be interested in

Cos 4θ − cos 2θ = sin θ

hichkok12 [17]

$cos(4\theta) - cos(2\theta) = sin(\theta)$
$-2sin(\frac{4\theta + 2\theta}{2})sin(\frac{4\theta - 2\theta}{2}) = sin(\theta)$
$-2sin(\frac{6\theta}{2}sin\frac{2\theta}{2}) = sin(\theta)$
$-2sin(3\theta)sin(\theta) = sin(\theta)$
$\frac{-2sin(3\theta)sin(\theta)}{-2sin(\theta)} = \frac{sin(\theta)}{-2sin(\theta)}$
$sin(3\theta) = -\frac{1}{2}$
$sin^{-1}[sin(3\theta)] = sin^{-1}(-\frac{1}{2})$
$3\theta = -30$
$\frac{3\theta}{3} = \frac{-30}{3}$
$\theta = -10$

7 0

3 years ago

I need help I don’t know how to Solve for 50=6.2x

tensa zangetsu [6.8K]

divide 50 by 6.2, because 6.2 and x are entangled by multiplication. once you do that, you will have your answer. it should be 8.06

4 0

3 years ago

Read 2 more answers

Please help me with this problem I will give brainliest

leva [86]

Answer:

second and last one