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Evgesh-ka [11]
3 years ago
15

I dont really know how to do soh cah toah. please help me find x.

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0
First notice that the triangle with sides x,y,a and the triangle with sides z,a+b,x are similar. This is true because the angle between sides x,y in the smaller triangle is clearly 30^\circ, while the angle between sides y,z in the larger triangle is clearly 60^\circ. So the triangles are similar with sides x,y,a corresponding to a+b,z,x, respectively.

Now both triangles are 30^\circ-60^\circ-90^\circ, which means there's a convenient ratio between its sides. If the length of the shortest leg is \ell_1, then the length of the longer leg is \ell_2=\sqrt3\ell_1 and the hypotenuse has length \ell_3=\sqrt{{\ell_1}^2+{\ell_2}^2}=2\ell_1.

Since x is the shortest leg in the larger triangle, it follows that a+b=2x, so a+b=15=2x\implies x=\dfrac{15}2
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Read 2 more answers
Please help me complete this !! 12points
Svet_ta [14]

Answer:

1.

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

2.

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

3.

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

4.

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

7.

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0
2 years ago
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