All categories

2 years ago

If you answer i will give you brainliest

Mathematics

1 answer:

PSYCHO15rus [73]2 years ago

6 0

Answer:

OK hiiiiiiiiiiiiiiiii.

You might be interested in

PLEASE HELP !!! :) :( Please!

Ludmilka [50]

Y= 1x + 8
both is increasing by one

8 0

3 years ago

Helpppp pls easy points

solmaris [256]

Answer:

153.94 is the area

Step-by-step explanation:

If the radius is 7p sqrt of 7p and you have your answer

The area of a circle is pi times the radius squared (A = π r²)

6 0

2 years ago

A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?

allsm [11]

Initial velocity=u=0m/s
Distance=s=150m
Time=t=10s
Acceleration=a

Using second equation of kinematics

$\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2$

$\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2$

$\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a$

$\\ \sf\longmapsto 50a=150$

$\\ \sf\longmapsto a=\dfrac{150}{50}$

$\\ \sf\longmapsto a=3m/s^2$

Mass=m=1000kg
Force=F

Using newtons second law

$\\ \sf\longmapsto F=ma$

$\\ \sf\longmapsto F=1000(3)$

$\\ \sf\longmapsto F=3000N$

3 0

2 years ago

Solve for c of the right triangle

Ede4ka [16]

In order to solve this triangle we must use cosine law:
$c^{2} = a^{2} + b^{2} - 2ab*cosC$

Now let's plug in the values we are given:
$c^{2} = 5^{2} + 8^{2} - 2(5)(8) * cos 67$
$c^{2} = 25 + 64 - 80*cos67$
$c = \sqrt{80-cos67}$

5 0

3 years ago

Read 2 more answers

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

3 years ago