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aniked [119]
3 years ago
12

Select all the correct answers.

Mathematics
1 answer:
NeX [460]3 years ago
8 0

Answer:

B and C

Step-by-step explanation:

y^{-8}y^{3}x^{0}x^{-2}=y^{-5}x^{-2}=\frac{1}{y^{5}x^{2}}

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D + 5.5 = 10. Solve for d.
Arte-miy333 [17]

Answer:

d=4.5

Step-by-step explanation:

d+5.5=10

d=10-5.5

d=4.5

Hope this is helpful

8 0
3 years ago
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A person is trapped in a burning building 60feet off the ground. A rescuer has a 70 foot ladder, but for safety purposes the lad
Neko [114]
Yes because, if the building is 60 ft from the ground and the ladder is 70 ft,shouldn’t it escalate an extra 10 ft because this is technically an emergency and it can be considered to be used as a reason for safety purposes, if I’m not mistaken
3 0
3 years ago
What's the greatest whole number that rounds to 621,860
Ad libitum [116K]
The greatest whole number that number that rounds to 621,860 is 621,864
5 0
3 years ago
A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents di
cupoosta [38]

Answer:

The probability value is almost equal to 0. Implying that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of decedents who died in the three-month period following their birthdays.

A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents died in the three-month period following their birthdays (123).

The probability (p) of anyone dying in any quarter if people die randomly during the year is simply 0.25.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 747 and p = 0.25.

But the sample selected is too large and the probability of success is small.

So a Normal approximation to binomial can be applied to approximate the distribution of <em>p</em> if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=747\times 0.25=186.75>10\\n(1-p)=747\times (1-0.46)=560.25>10

Thus, a Normal approximation to binomial can be applied.

So,  p\sim N(\hat p,\ \frac{\hat p(1-\hat p)}{n}).

Compute the probability that 46% or more would die in that particular interval if deaths occurred randomly throughout the year as follows:

P (p\geq 0.46)=P(\frac{p-\hat p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}>\frac{0.46-0.25}{\sqrt{\frac{0.25(1-0.25)}{747}}})

                   =P(Z>13.25)\\=1-P(Z

 *Use a <em>z</em> table for the probability.

The probability value is almost equal to 0. This probability is very low indicating that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

3 0
3 years ago
5
natulia [17]

Answer:

I think 1 day

Step-by-step explanation:

I am not sure :)

8 0
3 years ago
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