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3 years ago

Consider the Piece-Wise graph described by the following equation:

Mathematics

1 answer:

Scilla [17]3 years ago

8 0

Answer:

Hey, Dalilah. I hope I'm not too late, but the answer is (3,5).

Step-by-step explanation:

You have to use the equation that includes the x value of 3.

4x+1 only includes x values that are less than 3.

2x-1 includes x values that are greater than or equal to 3.

I plugged 3 into both of these equations (4x+1; x < 3 & 2x-1; x ≥ 3) in order to see which equation would've been true.

4(3)+1 = 13; 13 < 3 [False] 13 isn't less than 3 -- and 2(3)-1 = 5; 5 ≥ 3 [True] 5 is greater than or equal to 3.

Since the equation 2(3)-1; 5≥3 is true, you should use this equation. I used Demos in order to graph Y=2(3)-1. At the bottom of that I put x=3, and it showed me (3,5).

I'll post the pictures for proof and better clarification if this is confusing, love.

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An article suggests that a poisson process can be used to represent the occurrence of structural loads over time. suppose the me

kirill115 [55]

Answer:

a) $\lambda_1 = 2*2 = 4$

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

$X(2) \sim Poi (4)$

And the expected value is $E(X) = \lambda =4$

So we expect 4 number of loads in the 2 year period.

b) $P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]$

$P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]$

And we got: $P(X(2) >6) =1-0.889=0.111$

c) $e^{-2t} \leq 2$

We can apply natural log in both sides and we got:

$-2t \leq ln(0.2)$

If we multiply by -1 both sides of the inequality we have:

$2t \geq -ln(0.2)$

And if we divide both sides by 2 we got:

$t \geq \frac{-ln(0.2)}{2}$

$t \geq 0.8047$

And then we can conclude that the time period with any load would be 0.8047 years.

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution"

Solution to the problem

Let X our random variable who represent the "occurrence of structural loads over time"

For this case we have the value for the mean given $\mu = 0.5$ and we can solve for the parameter $\lambda$ like this:

$\frac{1}{\lambda} = 0.5$

$\lambda =2$

So then $X(t) \sim Poi (\lambda t)$

X follows a Poisson process

Part a

For this case since we are interested in the number of loads in a 2 year period the new rate would be given by:

$\lambda_1 = 2*2 = 4$

And let X our random variable who represent the "occurrence of structural loads over time" we know that:

$X(2) \sim Poi (4)$

And the expected value is $E(X) = \lambda =4$

So we expect 4 number of loads in the 2 year period.

Part b

For this case we want the following probability:

$P(X(2) >6)$

And we can use the complement rule like this

$P(X(2) >6) = 1-P(X(2)\leq 6)= 1-[P(X(2) =0)+P(X(2) =1)+P(X(2) =2)+...+P(X(2) =6)]$

And we can solve this like this using the masss function:

$P(X(2) >6) = 1- [e^{-4}+ \frac{e^{-4}4^1}{1!}+ \frac{e^{-4}4^2}{2!} +\frac{e^{-4}4^3}{3!} +\frac{e^{-4}4^4}{4!}+\frac{e^{-4}4^5}{5!}+\frac{e^{-4}4^6}{6!}]$

And we got: $P(X(2) >6) =1-0.889=0.111$

Part c

For this case we know that the arrival time follows an exponential distribution and let T the random variable:

$T \sim Exp(\lambda=2)$

The probability of no arrival during a period of duration t is given by:

$f(T) = e^{-\lambda t}$

And we want to find a value of t who satisfy this:

$e^{-2t} \leq 2$

We can apply natural log in both sides and we got:

$-2t \leq ln(0.2)$

If we multiply by -1 both sides of the inequality we have:

$2t \geq -ln(0.2)$

And if we divide both sides by 2 we got:

$t \geq \frac{-ln(0.2)}{2}$

$t \geq 0.8047$

And then we can conclude that the time period with any load would be 0.8047 years.

3 0

3 years ago

A teacher assigns a score from 1 to 4 to each student project. the table below shows the probability distribution of the scores

Mashutka [201]

The score which is assigned from 1 to 4 by the teacher to each student for the project and is most likely to be is 3 with 0.48 probability.

<h3>What is probability distribution?</h3>

Probability distribution is the statistical model which represent all the achievable and similar values of a random variable that it can possess in a specified range.

A teacher assigns a score from 1 to 4 to each student project. the table below shows the probability distribution of the scores for a randomly selected student.

Probability distribution score: 1, 2, 3, 4,
x probability: p(x) 0.06, 0.20, 0.48, 0.26

In the above data, the height probability of selection is 0.48. This probability belongs to the score 3.

Thus, the score which is assigned from 1 to 4 by the teacher to each student for the project and is most likely to be is 3 with 0.48 probability.

Learn more about the probability distribution here;

brainly.com/question/26615262

3 0

2 years ago

What value of x makes the equation below true 6x-7=26

VikaD [51]

Answer:

11/2

Step-by-step explanation:

6x−7=26

Step 1: Add 7 to both sides.

6x−7+7=26+7

6x=33

Step 2: Divide both sides by 6.

x= 11/2

6 0

3 years ago

Read 2 more answers

Alex drew two lines and two transversals. He wants to know the measures of angles 1, 2, and 3. Identify the measure of each angl

emmainna [20.7K]

Answer:

m 1 = 45 degrees because 1 and the angle measuring 135 degrees are supplementary angles.

m 2 = 95 degrees because 2 and the angle measuring 95 degrees are vertical angles.

m 3 = 40 degrees because 1, 2, and 3 form a triangle

Step-by-step explanation:

7 0

2 years ago

The function h is a quadratic function whose graph is a translation 7 units left and 9 units up of the parent function f(x) = x

slamgirl [31]

Answer:D ( if you add +4 to the (x + 3)^2)

Step-by-step explanation:

Parent function is f(x) = x^2

A translation 3 units left gives y = )x + 3)^2

- and 4 up gives y = (x + 3)^2 + 4 - vertex form.

Standard form :

y = x^2 + 6x + 9 + 4

= x^2 + 6x + 13.

6 0

2 years ago