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luda_lava [24]
3 years ago
13

Consider the Piece-Wise graph described by the following equation:

Mathematics
1 answer:
Scilla [17]3 years ago
8 0

Answer:

Hey, Dalilah. I hope I'm not too late, but the answer is <u><em>(3,5)</em></u>.

Step-by-step explanation:

You have to use the equation that includes the x value of <em>3</em>.

<em>4x+1</em> only includes x values that are less than <em>3</em>.

<em>2x-1</em> includes x values that are greater than or equal to <em>3</em>.

I plugged <em>3</em> into both of these equations <em>(4x+1; x < 3 & 2x-1; x ≥ 3)</em> in order to see which equation would've been true.

<em>4(3)+1 = 13; 13 < 3 [False] 13 isn't less than 3 -- and 2(3)-1 = 5; 5 ≥ 3 [True] 5 is greater than or equal to 3.</em>

Since the equation <em>2(3)-1; 5≥3</em> is true, you should use this equation. I used <em>Demos</em> in order to graph <em>Y=2(3)-1</em>. At the bottom of that I put <em>x=3</em>, and it showed me <em>(3,5)</em>.

I'll post the pictures for proof and better clarification if this is confusing, love.

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Step-by-step explanation:

I guess we only need to add 2 hours and 38 minutes to the depart times to get arrival, and deduct 2 hours and 38 minutes from arrival to get departure.

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2 years ago
Larissa argued that since log2(2) = 1 and log2(4) = 2, then it must be true that log2(3) = 1.5. Is she correct?
mestny [16]

Answer:

2^{1.5} = 2.8284. This means that Larissa is not correct.

Step-by-step explanation:

To solve logarithms, we have to consider the following:

\log_{a}(b) = c means that a^{c} = b.

So, for example:

log_{2}(2) = 1 because 2^{1} = 2.

log_{2}(4) = 2 because 2^{2} = 4.

If 2^{1.5} = 3, then Larissa is correct. However, 2^{1.5} = 2.8284. This means that Larissa is not correct.

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3 years ago
Isabel stacked two wooden blocks as shown. What is the total volume of the stacked blocks?
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9514 1404 393

Answer:

  156 cm³

Step-by-step explanation:

The volume of any prism is the product of the base area and the height of the prism. Here, we can take the "base" to be the front face of the assembly, and its "height" to be the 3 cm distance between the front and back faces.

The front face area is the sum of the triangle area and the rectangle area.

  A = 1/2bh + LW

  A = (1/2)(10 cm)(4 cm) + (16 cm)(2 cm) = 52 cm²

Then the volume is ...

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Answer:

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2 years ago
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