Answer:
-12
Step-by-step explanation:
ds/dt = d/dt ( 1-12 t)
ds/dt = -12
When t=2
ds/dt = -12
Answer:
The unit vector u is (-5/√29) i - (2/√29) j
Step-by-step explanation:
* Lets revise the meaning of unit vector
- The unit vector is the vector ÷ the magnitude of the vector
- If the vector w = xi + yj
- Its magnitude IwI = √(x² + y²) ⇒ the length of the vector w
- The unit vector u in the direction of w is u = w/IwI
- The unit vector u = (xi + yj)/√(x² + y²)
- The unit vector u = [x/√(x² + y²)] i + [y/√(x² + y²)] j
* Now lets solve the problem
∵ v = -5i - 2j
∴ IvI = √[(-5)² +(-2)²] = √[25 + 4] = √29
- The unit vector u = v/IvI
∴ u = (-5i - 2j)/√29 ⇒ spilt the terms
∴ u = (-5/√29) i - (2/√29) j
* The unit vector u is (-5/√29) i - (2/√29) j
Answer:
"number line with open circles on negative 9 and 5, shading going in the opposite directions."
Step-by-step explanation:
Your inequality doesn't include an equal sign so there will be no closed holes. It will only be open holes.
|u|>14 means that the number u has to be greater than 14 or less than -14. These numbers I describe just now all have a distance greater than 14 from 0.
So |u|>14 implies u>14 or u<-14.
But we are solving |2x+4|>14 so this implies we have 2x+4>14 or 2x+4<-14.
2x+4>14
Subtract 4 on both sides:
2x >10
Divide both sides by 2:
x >5
2x+4<-14
Subtract 4 on both sides:
2x <-18
Divide both sides by 2:
x <-9
So our solution is x>5 or x<-9.
Graphing!
~~~~~~~O O~~~~~~~~
-----------(-9)---------------------------------(5)---------------
So we shaded to the right of 5 because our inequality says x is bigger than 5.
We shaded to the left of -9 because our inequality says x is less than -9.
Answer:
The ball will strike the ground at time t = 21sec .
The two complementary angles are:
95° and 15°
Step-by-step explanation:
Let x be one angle
then the other angle will be 90-x
As the sum of complementary angles is 90
So,
then according to statement

The two complementary angles are:
95° and 15°
Keywords: Angles, triangles
Learn more about angles at:
#LearnwithBrainly