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Ipatiy [6.2K]
3 years ago
5

The value of 8 In 686,293

Mathematics
2 answers:
olga_2 [115]3 years ago
6 0
The answer is 80,000
Orlov [11]3 years ago
5 0
Eighty thousand or 80,000
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Solve each equation.<br> 1/3a = -5 a = ?<br> 12 - b = 12.5 b = ? <br> -0.1 = -10c c = ?
Rina8888 [55]

Answer:

a = -15, b = -.5, c = -1

Step-by-step explanation:

1/3a = -5 --> multiply each side with 3 --> a = -15

12 - b = 12.5 --> subtract 12 from both sides --> -b = .5 --> multiply each side with -1 to get b positive --> b = -.5

.1 = -10c --> multiply each side with -10 --> c = -1

8 0
3 years ago
PLS HELP!!!! I NEED TO FIND THE SURFACE AREA OF THIS CYLINDER!!!!!
Hunter-Best [27]
I think the answer is 2990.8 c.m
Hope that helps :)
5 0
3 years ago
Grace is three times as old as Hans, but in 5 years she will be twice as old as Hans is then. How old are they now? Set up an th
frosja888 [35]

Answer:

3x - y = 0; 2x - y = -5

Step-by-step explanation:

Let x be the present age of Hans and y be the present age of Grace,

Since, in present Grace is three times as old as Hans,

⇒ y = 3x

⇒ 3x - y = 0

Now, after 5 years,

The age of Hans = x + 5,

And, the age of Grace = y + 5

Also, in 5 years Grace will be twice as old as Hans is then,

⇒ y + 5 = 2 ( x + 5 )

⇒ y + 5 = 2x + 10

⇒ 2x - y = -5

Hence, the required system of linear equations is,

3x - y = 0; 2x - y = -5

5 0
3 years ago
What is the probability that if you multiply two randomly-selected two-digit whole numbers, the result is greater than 100 and l
ohaa [14]

Answer:

4/675

Step-by-step explanation:

There can be 90  two-digit numbers ranging from 10 to 99. There will be

90 x 90= 8100 possibilities of randomly selecting and combining 2 entire two-digit numbers, if we find ax b to be distinct from bx a. When 10 is first chosen, there may be 9 two-digit numbers that could be combined within the required range for a product When 11 is chosen first, then the second two-digit number has 9 possibilities. 12 has seven options; 13 has six options; 14 has five options; 15 has four options; 16 has three options; 17 has two options; 18 has 2 options; and 19 has one option. It provides us 48 total choices so the likelihood that the combination of two randomly chosen two-digit whole numbers is one of theses  these possibilities is thus 48/8100 = 4/675.

8 0
3 years ago
What is the amount of a $4,000.00 annuity due at 12 percent compounded semiannually for 3 years?
Dmitriy789 [7]

Answer:

$ 5674.076

Step-by-step explanation:

The question is on compound interest

The formulae = A= P(1+ r/n) ^nt .......where P is the principal amount, r is the rate of interest in decimal, n is number of compoundings per year and t is the total number of years.

Given; P= $4,000.00 , r=12/100=0.12, n=2 and t=3

Substituting values in the equation  A= P(1+ r/n) ^nt

A= 4000 ( 1+0.12/2)^2×3

A=4000(1.06)^6

A=$ 5674.08

3 0
3 years ago
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