With one point of the compass on the vertex of the angle, draw an arc that intersects both sides of the angle. Draw an arc from each of these points of intersection so that the arcs intersect<span> in the interior of the angle. The compass needs to </span>stay open<span> the same amount throughout this step.
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Answer:
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Step-by-step explanation:
<u>Area of ABCD = L * W</u>
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
<u>Area of EFGC:- L * W</u>
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
<u>Now, the area of the combind rectangles:-</u>
ABCD + EFGC
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Volume=legnth times width times height
since it is a cube, legnt=width=height so
volume=height^3 or width^3 or legnth ^3 so
height =5 so
5^3=5 times 5 times 5=125 cubic inches
the answer is C
Since y intercept if one, i automatically know the answer is y = 1/2x + 1. The second one
Volume of a cylinder is h x r^2 x pi
You have the volume and radius of each one, so taking 188.4=(2)^2 x 3.14 x h1, you can solve this equation for the height h1. Likewise, for the other graduated cylinder you take 314=2^2 x 3.14 x h2, and then solve for h2.
To get the difference in heights, just take h2-h1 after solving the equations for h2 and h1