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3 years ago

Factor the trinomial by grouping. 9x^3 - 3x^2 -30x

Mathematics

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

3x(3x+5)(x-2)

Step-by-step explanation:

$9x^3-3x^2-30x= \\\\3x(3x^2-x-10)= \\\\3x(3x^2+5x-6x-10)= \\\\3x(x(3x+5)-2(3x+5))= \\\\3x(3x+5)(x-2)$

Hope this helps!

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Im not sure b right or wrong?

katen-ka-za [31]

Answer:

Yes That is right. B is correct

Step-by-step explanation:

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Ten more than 6 times Harold age is the same as 4 times his age is increased by 40. Find Harold’s age

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JulsSmile [24]

Answer:

$\% Below\ 50 = 88 \%$

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Step-by-step explanation:

Given

$Total = 200$

<em>The attachment presents the table properly</em>

Solving (a): Percentage of those who play for less than 50 hours weekly

To do this, we simply consider the frequency of students that fall within:

1.0 - 7.9, 8.0 - 14.9,......,43.0 - 49.9

Their frequency is:

$Frequency = 21 + 37 + 40 + 27 + 23 + 18 + 10$

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$\% Below\ 50 = \frac{176* 100}{200} \%$

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Solving (b): Percentage of those who play for 43 or more hours weekly

To do this, we simply consider the frequency of students that fall within:

43.0 - 49.9,......,64.0 - 70.9

Their frequency is:

$Frequency = 10 + 7 + 5+12$

$Frequency = 34$

The percentage is then calculated as:

$\% 43\ or\ more = \frac{Frequency}{Total} * 100\%$

$\% 43\ or\ more = \frac{34}{200} * 100\%$

$\% 43\ or\ more = \frac{34* 100}{200} \%$

$\% 43\ or\ more = \frac{34* 1}{2} \%$

$\% 43\ or\ more = \frac{34}{2} \%$

$\% 43\ or\ more = 17 \%$

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Answer:

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Answer:

Step-by-step explanation:

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