Question

The number of road construction projects that take place at any one time in a certain city follows a Poisson distribution with a mean of 6. Find the probability that less than 3 road construction projects are currently taking place in this city.a) 0.050409b) 0.089235c) 0.301168d) 0.014936

Answer 1

Answer:

The probability that less than 3 road construction projects are currently taking place in this city is 0.06197

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distribution with a mean of 6.

This means that $\mu = 6$

Find the probability that less than 3 road construction projects are currently taking place in this city.

This is:

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197$

The probability that less than 3 road construction projects are currently taking place in this city is 0.06197