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yan [13]
3 years ago
10

1 and 2 are vertical angles. If the measure of 22 is 105°, find the measure of

Mathematics
1 answer:
sergey [27]3 years ago
6 0
If i am not wrong the question of this woyld be the measure of 1 right . Because both of these are vertical angle so they are equal to each other “><“ like that so measure of 1 is 105 tô
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HELP ASAP!!!20pts<br><br> 1/3x=−20<br><br> WHAT IS X?
zmey [24]

Answer:

x = -60

Step-by-step explanation:

1/3x=−20

X is 1/3

X times 3 = a full X

Fill it in

X times -20 = -60

Hope this helps :)

7 0
3 years ago
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Marco can finish a jigsaw puzzle in 3 hours. Working together with Cliff, it takes them 1 hour. How
vovikov84 [41]

Macro can finish the puzzle in 3 hours. We can say that her speed for working is 1/3 or 1/3 puzzle per hour.

Now if they work together, this turns into 1 puzzle per hour.

That must mean that Cliff would be doing the other 2/3 of the puzzle while Macro does his 1/3 in that hour. If Cliff has a speed of doing them 2/3 per hour. Then it would take 1 and a half hour to finish 1 whole puzzle.

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3 years ago
The difference of a number times 2 and 3 equals 8.
laiz [17]
I think the answer is 2 but I'm not sure
8 0
3 years ago
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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Express (16³) 1/4 in simplest radical form.
Doss [256]

Answer:

70

Step-by-step explanation:

4 0
2 years ago
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