The answer is not a linear equation and the graph is decreasing. sorry i had made a mistake the first time
No they won’t be.Consider the linear combination (1)(u – v) + (1) (v – w) + (-1)(u – w).This will add to 0. But the coefficients aren’t all 0.Therefore, those vectors aren’t linearly independent.
You can try an example of this with (1, 0, 0), (0, 1, 0), and (0, 0, 1), the usual basis vectors of R3.
That method relied on spotting the solution immediately.If you couldn’t see that, then there’s another approach to the problem.
We know that u, v, w are linearly independent vectors.So if au + bv + cw = 0, then a, b, and c are all 0 by definition.
Suppose we wanted to ask whether u – v, v – w, and u – w are linearly independent.Then we’d like to see if there are non-zero coefficients in the linear combinationd(u – v) + e(v – w) + f(u – w) = 0, where d, e, and f are scalars.
Distributing, we get du – dv + ev – ew + fu – fw = 0.Then regrouping by vector: (d + f)u + (-d +e)v + (-e – f)w = 0.
But now we have a linear combo of u, v, and w vectors.Therefore, all the coefficients must be 0.So d + f = 0, -d + e = 0, and –e – f = 0. It turns out that there’s a free variable in this solution.Say you let d be the free variable.Then we see f = -d and e = d.
Then any solution of the form (d, e, f) = (d, d, -d) will make (d + f)u + (-d +e)v + (-e – f)w = 0 a true statement.
Let d = 1 and you get our original solution. You can let d = 2, 3, or anything if you want.
Answer:
-10/1 is simplified for 30/3
hope this helps
Answer:
We can use a trick here. Let's look at the first few exponents of i to realize this:
i^0 = 1
i^1 = i
i^2= -1
i^3 = -i
i^4 = 1
i^5 = i
i^6 = -1
i^7 = -i
we can see that the pattern (1, i, -1, -i) repeats. Since 82/2 = 41, and 41 is only divisible by 1, i^41 = i, and i^2 = -1. -1*i = -i, so i^82 = -i.
Step-by-step explanation:
Answer:
Expected value would be $ 0.896
Step-by-step explanation:
Given,
The price of the lottery ticket = $44800000,
Also, the probability of winning the grand prize = .000000020,
Thus, the expected value of the lottery ticket = value of the lottery ticket × probability of getting the lottery ticket
= 44800000 × .000000020
= $0.896
Note : value of lottery ticket = prize amount - cost of each ticket,
Here the cost price of a ticket is not given,
That's why we did not consider it.
