All categories

3 years ago

Which inequality represents all the solutions of -5x + 5 ≥ 160 − 10x? A. x ≤ -33 B. x ≥ 33 C. x ≥ 31 D. x ≤ 31

Mathematics

2 answers:

olganol [36]3 years ago

4 0

Answer:

yea its b lol

Step-by-step explanation:

ikadub [295]3 years ago

3 0

Answer:

The answer is B.

Step-by-step explanation:

Solve for x.

-5x + 5 $\geq$ 160 - 10x

Add 10x to both sides, and subtract 5 from both sides.

5x $\geq$ 155

Now, divide by 5.

x $\geq$ 31 is the answer

#teamtrees #WAP (Water And Plant)

You might be interested in

Write an equation of the line that passes through the point (-6, -9) with slope-5.

Art [367]

Answer:

$y+9=-5(x+6)$

Step-by-step explanation:

We are being asked to write the equation in point-slope form:

$y-y_1=m(x-x_1)$ where m = slope and the first point = $(x_1,y_1)$

In this case, the slope is -5 and the point is $(-6,-9)$ so the equation will be:

$y+9=-5(x+6)$

Want to learn more about point-slope form? Check the link out:

https://www.albert.io/blog/point-slope-form/#What_is_point_slope_form

3 0

3 years ago

What is the area of a rectangular rug that<br> measures 8 1/4 feet by 10 3/4 feet?<br> Area:

ziro4ka [17]

Answer:

Step-by-step explanation:

$= 8 \frac{1}{4} \times 10 \frac{3}{4}$

$= \frac{33}{4} \times \frac{43}{4}$

$= \frac{1419}{4}$

$= 354 \frac{3}{4} \: \: feet$

7 0

3 years ago

Samantha’s college runs on a trimester schedule so she receives a bill 3 times a year for tuition. Each trimester costs $1,450,

matrenka [14]

3 times a year for 2 years is equal to 3 x 2, or 6. So we know that she will have to pay her bill 6 times.

The cost for each trimester is $1450, but we still have to add the book costs ($350). So, 1450 + 350 = 1800.

Now we know that she has to pay $1800 six times. So the equation will be:

1800 x 6 = 10800.

It will cost Samantha $10,800 to get her degree.

8 0

3 years ago

Read 2 more answers

Please help me....I really need help!!

scoundrel [369]

$\dfrac{c^2-4}{6c^4+15c^3}\div\dfrac{c^2+4c+4}{12c^3+30c^2}=\dfrac{c^2-2^2}{3c^3(2c+5)}\div\dfrac{c^2+2(c)(2)+2^2}{6c^2(2c+5)}\\\\_{\text{use}\ a^2-b^2=(a-b)(a+b)\ \text{and}\ (a+b)^2=a^2+2ab+b^2}\\\\=\dfrac{(c-2)(c+2)}{3c^3(2c+5)}\cdot\dfrac{6c^2(2c+5)}{(c+2)^2}=\dfrac{(c-2)}{c}\cdot\dfrac{2}{(c+2)}=\boxed{\dfrac{2(c-2)}{c(c+2)}}$

6 0

3 years ago

Which numbers are irrational?

ira [324]

Wish I could help I’m not good at math

6 0

3 years ago