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Naya [18.7K]
3 years ago
5

If you can buy 1⁄3 of a box of chocolates for 6 dollars, how much can you purchase for 4 dollars? Write your answer as a fractio

n of a box.
Mathematics
2 answers:
Nimfa-mama [501]3 years ago
5 0

Answer:

\frac{2}{9} of a box of chocolate .

Step-by-step explanation:

Given :  you can buy 1⁄3 of a box of chocolates for 6 dollars,

To find :  how much can you purchase for 4 dollars.

Solution : We have given that

For 6 dollars we can buy = \frac{1}{3} of a box.

For 1 dollar we can buy  = \frac{1}{3}÷ 6.

For 4 dollar we can buy =  \frac{1}{18} ×4

                                        =   \frac{2}{9} of a box of chocolate .

Therefore, \frac{2}{9}of a box of chocolate .

Stella [2.4K]3 years ago
3 0
Given that 1/3 of a box is 6 dollars, we can say that per dollar is 1/18 of a box. If you have 4 dollars, this would mean that you can buy 4/18 of a box to 2/9 of a box. Hope this answers your question. Have a great day ahead!
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5 times 7 is 35

Mark me as brainliest if this helps!

5 0
3 years ago
Nancy prepared 12 kilograms of dough after working 6 hours. How much dough did Nancy prepare if she worked for 10 hours? Solve u
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3 years ago
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Reuben bought a desktop computer and a laptop computer. Before finance charges, the laptop cost $150 more than the desktop. He p
cupoosta [38]
Same case as Pablo's, more or less.

a = price for the desktop

b = price for the laptop

we know the laptop is 150 bucks more than the desktop,  b = a + 150.

how much is 7% of a?  (7/100) * a, 0.07a.

how much is 9.5% of b?  (9.5/100) * b, 0.095b.

total interests for the financing add up to 303, 0.07a + 0.095b = 303.

\bf \begin{cases}
\boxed{b}=a+150\\
0.07a+0.095b=303\\
----------\\
0.07a+0.095\left(\boxed{a+150}  \right)=303
\end{cases}
\\\\\\
0.07a+0.095a+14.25=303\implies 0.165a=288.75
\\\\\\
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how much was it for the laptop?  well b = a + 150.
8 0
3 years ago
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