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Ber [7]
3 years ago
5

Consider the following 8 numbers, where one labelled

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0
<h3>Answers:     x = -17  and   x = 64</h3>

====================================================

Explanation

Consider three scenarios:

  • A) The value of x is the smallest of the set (aka the min)
  • B) The value of x is the largest of the set (aka the max)
  • C) The value of x is neither the min, nor the max. So 8 < x < 39.

These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.

--------------------

We'll start with scenario A.

If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}

The range is 56, so,

range = max - min

56 = 39 - x

56+x= 39

x = 39-56

x = -17  which is one possible answer

--------------------

If instead we go with scenario B, then x is the max and 8 is the min

range = max - min

56 = x - 8

56+8 = x

64 = x

x = 64 is the other possible answer

--------------------

Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.

Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.

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BARSIC [14]
A multiplication expression with a product of 5 to the 13th power is...
    - 5 • 5 • 5 • 5 • 5 • 5 • 5 • 5 • 5 • 5 • 5 • 5 • 5 = 1,220,703, 125 (answer)
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I am 99.9% sure that this is the correct answer, but if it happens not to be, I am truly sorry, and I hope you can forgive me. Thank You!
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How do I do this im having trouble and its my exam day?
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Answer:

C.

Step-by-step explanation:

So basically set (10x-13) equal to (3x+22) and then solve for x

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