Try writing it in point-slope form and you will see why you have a problem.
slope m is equal to (y2-y1)/(x2-x1):
m = (y2-y1)/(x2-x1) = (2-6)/(-6 - -6) = -4/0
The denominator has a zero, so it is undefined.
Since the point-slope form requires "m" to be defined, you can't write the equation of the line using point-slope form.
No, i don't think it's true
Answer:
f ( - 2 ) = - 12
Step-by-step explanation:
f ( - 2 ) = - 3 ( -2 )^2
then you do the exponent first so
- 3 ( 4 )
now you multpily the - 3 and 4
you get - 12
A quadrilateral is a polygon with 4 number of sides and 4 vertices. The shape of the field is either square or a rhombus.
<h3>What is a quadrilateral?</h3>
A quadrilateral is a polygon with 4 number of sides and 4 vertices. A few examples of a quadrilateral are square, rectangle, rhombus, parallelogram, etc.
Given that ABCD represents a field, therefore, the field is a quadrilateral. Now, as the path is going between the field. And starts from A therefore, it will end at C.
Since It is the same distance from BA and BC. Therefore, it will be the diagonal of the quadrilateral. And as BA and BC are consecutive sides and are of the same length.
Hence, the shape of the field is either square or a rhombus.
Learn more about Quadrilateral:
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