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asambeis [7]
4 years ago
10

A triangle drawn on a map has sides that measure 15 cm, 8 cm, and 10 cm. The shortest of the corresponding real-life distances i

s 127 km. Find the longest of the real-life distances.
Mathematics
1 answer:
nalin [4]4 years ago
5 0

Set up a proportion.

8/127=15/x

Cross multiply

8x=1,905

Divide both sides by 8

x=238.125

The longest of the real-life distances is 238.125 km.

Hope this helps :)

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Translate this sentence into an equation.
lana [24]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Ray UW is the angle bisector of VUT. If mVUW = (4x + 6)° and mWUT = (6x – 10)°, what is the measure of WUT? 32° 38° 48° 76°
stepan [7]
Ray UW bisect VUT it means it must be breaking them in two equal parts
VUT=VUW+WUV
and mVUW= mWUV
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mWUT=6x-10=6(8)-10=38°

Your answer is 38°


4 0
3 years ago
Read 2 more answers
Please help me with this
Masja [62]

Answer:

c = a - 16

Step-by-step explanation:

Given

a = b + 12 ( subtract 12 from both sides )

a - 12 = b

Substitute b = a - 12 into b = c + 4

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5 0
2 years ago
A total of 765 tickets were sold for the school play. They were either adults or students tickets. There were 65 more student ti
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Answer: 350 adult tickets

Step-by-step explanation:

(omg I remember this question!)

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student tickets : a + 65

<em>the equation for the prob: </em>

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<em>solve:</em>

combine 'like terms'

1.) 765 = a + a + 65

2.) 765 = 2a + 65

<u>- 65         - 65 </u>

700= 2a

divide by 2

700/2 = 2a/2

<em>(700/2 = 350) </em>

<em>(the "2" in 2a is cancelled out by the other 2)</em>

<u>350 = a </u>

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