Answer:
The gas will occupy a volume of 1.702 liters.
Explanation:
Let suppose that the gas behaves ideally. The equation of state for ideal gas is:
(1)
Where:
- Pressure, measured in kilopascals.
- Volume, measured in liters.
- Molar quantity, measured in moles.
- Temperature, measured in Kelvin.
- Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.
We can simplify the equation by constructing the following relationship:
(2)
Where:
,
- Initial and final pressure, measured in kilopascals.
,
- Initial and final volume, measured in liters.
,
- Initial and final temperature, measured in Kelvin.
If we know that
,
,
,
and
, the final volume of the gas is:
![V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%20%5Cleft%28%5Cfrac%7BT_%7B2%7D%7D%7BT_%7B1%7D%7D%20%5Cright%29%5Ccdot%20%5Cleft%28%5Cfrac%7BP_%7B1%7D%7D%7BP_%7B2%7D%7D%20%5Cright%29%5Ccdot%20V_%7B1%7D)
![V_{2} = 1.702\,L](https://tex.z-dn.net/?f=V_%7B2%7D%20%3D%201.702%5C%2CL)
The gas will occupy a volume of 1.702 liters.