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3 years ago

14

How does the freezing and boiling point of ocean water compare to those of distilled water?

1 answer:

vichka [17]3 years ago

8 0

Distilled water is touched by man so it would probably be close to 300 degrees farenheit.......maybe.

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2 years ago

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Which of the following theories provides information concerning both molecular shape and molecular bonding?

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I believe the answer is orbital hybridization theory

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3 years ago

1. The calendar below shows a sample month of the year. Suppose that you see a full moon on the first day of this month.

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3 years ago

A force of 20 N acts upon 5 kg block caculate the accerleration of the object

Vedmedyk [2.9K]

Answer:

$\boxed{\text{4 m $\cdot$ s$^{-2}$}}$

Explanation:

F = ma

$a = \dfrac{F}{m} = \dfrac{\text{20 N}}{\text{5 kg}} \times \dfrac{\text{1 kg$\cdot$ m $\cdot$ s$^{-2}$}}{\text{1 N}} = \text{4 m $\cdot$ s$^{-2}$}\\\\\text{The acceleration of the object is } \boxed{\textbf{4 m $\cdot$ s$^{\mathbf{-2}}$}}$

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3 years ago

Calculate the energy (in kJ) required to heat 10.1 g of liquid water from 55 oC to 100 oC and change it to steam at 100 oC. The

Maksim231197 [3]

Answer:

$\large\boxed{\large\boxed{24.6kJ}}$

Explanation:

<u>1. Energy to heat the liquid water from 55ºC to 100ºC</u>

$Q=m\times C\times \Delta T$

m = 10.1g

C = 4.18g/JºC

ΔT = 100ºC - 55ºC = 45ºC

$Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J$

<u>2. Energy to change the liquid to steam at 100ºC</u>

$L=\lambda \times n$

λ = 40.6kJ/mol

n = 10.1g / 18.015g/mol = 0.5606mol

$L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J$

<u>3. Total energy</u>

$1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ$

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3 years ago