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mezya [45]
3 years ago
6

Four processes that change rock from one type to another.

Chemistry
1 answer:
Cloud [144]3 years ago
8 0
Erosion
waethring
deposition
pressure or heat 
all of this can change the form of rock to another
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One sound is loud and another is quieter. What must be different about these two sound waves?
tankabanditka [31]
Loudness of the sound depends on the "Amplitude" as loudness is different for two waves, their Amplitude must be different

In short, Your Answer would be "Amplitude"

Hope this helps!
3 0
3 years ago
Enter the ionic equation, including phases, for the reaction of AgNO3(aq) with K2SO4(aq).
gogolik [260]
 The answer is 
2Ag+(aq) + SO4-2(aq) → Ag2SO4(s) 

<span>NO3- and K+ ions are spectators </span>
3 0
3 years ago
If 3.75 moles of aluminum react, how many moles of sulfur are needed?
aliya0001 [1]

Answer:(A) 0.70 mol

Explanation:

5 0
3 years ago
If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.
kicyunya [14]
Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

CH_{3}COOH \ \textless \ ---\ \textgreater \   H^{+} + CH_{3}COO^{-}

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> [H^{+}]  = 10^{-2.88} =  0.001 moldm^{-3}

The change in Concentration Δ [CH_{3}COOH]= 0.001 moldm^{-3}


                                  CH3COOH          H+           CH3COOH    
Initial  moldm^{-3}                      x           0                     0
                                                                                                                       
Change moldm^{-3}        -0.001            +0.001           +0.001
                                                                                                       
Equilibrium moldm^{-3}      x- 0.001      0.001             0.001
                                                                              

Since the k_{a} value is so small, the assumption 
[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium} can be made.

k_{a} = [tex]= 1.8*10^{-5}  =  \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} =  \frac{0.001^{2}}{x}

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

         2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps! 



8 0
3 years ago
Which excerpt from “Seventh Grade” is an example of an internal expectation?
alex41 [277]
A. Theresa is going to be my girl this year, he promised himself as he left the gym full of students in his new fall clothes.
6 0
3 years ago
Read 2 more answers
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