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Elanso [62]
3 years ago
5

2.Which of the alcohols listed below would you expect to react most rapidly with PBr3?A)CH3CH2CH2CH2CH2CH2OHB)(CH3CH2)2CH(OH)CH2

CH3C)(CH3CH2)2CHOHCH3D)(CH3CH2)3COHE)(CH3CH2)2C(CH3)OH

Chemistry
1 answer:
Gnoma [55]3 years ago
7 0

Answer:

A) CH3CH2CH2CH2CH2CH2OH

Explanation:

For this question, we have the following answer options:

A) CH3CH2CH2CH2CH2CH2OH

B) (CH3CH2)2CH(OH)CH2CH3

C) (CH3CH2)2CHOHCH3

D) (CH3CH2)3COH

E) (CH3CH2)2C(CH3)OH

We have to remember the<u> reaction mechanism</u> of the substitution reaction with PBr_3. <em>The idea is to generate a better leaving group in order to add a "Br" atom.</em>

The PBr_3 attacks the "OH" generation new a bond to P (O-P bonds are very strong), due to this new bond we will have a better leaving group that can remove the oxygen an allow the attack of the Br atom to generating a new C-Br bond. This is made by an <u>Sn2 reaction</u>. Therefore we will have a faster reaction with <u>primary substrates</u>. In this case, the only primary substrate is molecule A. So, <em>"CH3CH2CH2CH2CH2CH2OH"</em> will react faster.

See figure 1

I hope it helps!

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kvv77 [185]

Answer:

Percentage by mass of calcium carbonate in the sample is 93.58%.

Explanation:

Assumptions:

  • calcium carbonate was dissolved completely and the amount of carbon dioxide released was proportional to the amount of calcium carbonate.
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PV = nRT

n = \frac{PV}{RT}

P = 791 mmHg = \frac{791 mmHg}{760 mmHg} x 1 atm = 1.040789 atm.

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T = 20^{0}C + 273^{0} C = 293 K

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given the equation of the reaction:

CaCO_{3}  + 2HCL =  CaCl_{2}  + CO_{2} + H_{2}O

from assumption:

amount carbon dioxide = amount of calcium carbonate

n(CaCO_{3} ) = n(CO_{2} )

reacting mass ( m )  = Molar Mass ( M ) * Amount ( n )

m(CaCO_{3} )   =   n(CaCO_{3} )  *   M(CaCO_{3} )

m = 0.04938397 mol * 100 \frac{g}{mol} =  4.93839 g

percentage by mass of   CaCO_{3} = \frac{mass of pure  }{mass of impure}*100  = \frac{4.93839g}{5.28g}*100  = 93.5802%.

8 0
3 years ago
Name the following hydrocarbons
Yakvenalex [24]

Answer:

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Explanation:

On the first molecule, we have a methyl group on the 3rd carbon, so you will have "3-methhyl". It's a 5 carbon molecule with no double bonds, so "-pentane" is required.

On the second molecule, we have a simple 4 carbon molecule with a triple bond which makes it an Alkyne. 4 carbons makes the prefix "but-" and a alkyne males the ending "-yne".

8 0
3 years ago
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= 3.89 x 10²¹ molecules

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8 0
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4 0
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Answer:

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Explanation:

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 Then;

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