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UNO [17]
2 years ago
9

Write the equations for the graphs below (worth 5 points) ​

Mathematics
2 answers:
serg [7]2 years ago
3 0
Answers:

10) y= 1/2x - 2
11) y= 2x + 3
12) y= 2/3x - 4

I found this by using y=mx+ b
brilliants [131]2 years ago
3 0
Umm the 3rd one pick to see if right then hall at me
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y=f(x) is odd (f(-x)=-f(x)) and f(x>0) = x^2-5x-12, x is not = to 0. What points does the line f(x)=12 go through.
solmaris [256]
<span>f(x<0)=-f(x>0)=-x^2+5x+12 When x>0, x^2-5x-12=12, x=8, y=12 Therefore, f(x)=12 goes through point (8,12).</span>
5 0
3 years ago
Ellen says that one and 2/5 equal 5÷7. Is she correct? Explain.
zhuklara [117]
No because 2/5 is the same as 2 divided by 7, so 2/5 = 0.4 where 5 divide by 7 is 0.714….. so they’re not equal.
7 0
2 years ago
Which three-dimensional object can be formed by rotating a rhombus about one of its diagonals?
Ghella [55]
Shape 3 is the correct answer


6 0
3 years ago
The exponential decay graph shows the expected depreciation for a new boat, selling for $3500, over 10 years a. Write an exponen
Alex Ar [27]
For the answer to the question above,  
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years. 
V(0) = 3500 
V(2) = 2000 

n = 0 
V(0) = a * b^0 = 3500 
a = 3500 

V(2) = a * b^2 
2000 = 3500 * b^2 
b = sqrt (2000/3500) 
b ≈ 0.76 

V(n) = 3500 * 0.76^n 

We can check it for n = 1 which is close to 2500 in the graph: 
V(1) = 3500 * (0.76)^1 
V(1) = 2660 

And in the graph we have V(3) ≈ 1500, 
V(n) = 3500 * (0.76)^3 ≈ 1536 

Now n = 9.5 
V(9.5) = 3500 * (0.76)^(9.5) 
V(9.5) ≈ 258</span>
4 0
3 years ago
Read 2 more answers
Select the correct answer.
zhannawk [14.2K]
You have a good day and good luck on that question
8 0
3 years ago
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