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3 years ago

For the following set of data, find the percentage of data within 2

Mathematics

1 answer:

Maru [420]3 years ago

8 0

Answer:

58,+77,+31,+54+,58+,54+,46+,58+,56/9

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0.12 times 0.08 divided by 2.40

blagie [28]

Answer:

Step-by-step explanation:

515615151

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3 years ago

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Suppose a class of 50 students has 20 males and 30 females. The insturctor will pick 1 (different) student to compete in 3 diffe

Pie

Answer:

Step-by-step explanation:

Total = 50

Males = 20

Females = 30

a) P(exactly 1 female) = P(1 female , 2 male)

(30C1 * 20C2) / (50C3) = 30*190/19,600 = 0.2908

b) P(at least 2 males) = 1 - (P(0 males) + P(1 males))

= 1 - 30C3 * 20C0/50C3 - 30C2 * 20C1/50C3

= 1 - 4060*1/19,600 - 435*20/19,600 = 6840/19600 = 0.3489

4 0

4 years ago

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4xsquared 12x 10 is less than or equal to 0 (or what multiplies to get 40 and adds to get 12)

g100num [7]

It either x=5 or x=-2 not sure which on

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3 years ago

Which is the same as 100 and 6 tens

BARSIC [14]

6 tens is 60
100+60=
160
Hope this helps.

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3 years ago

Prove that :

Dimas [21]

Answer:

<h3>Question 1</h3>

sec²θ + cosec²θ =
1/cos²θ + 1/sin²θ =
(sin²θ + cos²θ)/(sin²θcos²θ) =
1 / (sin²θcos²θ) =
[(sin²θ + cos²θ)/sinθcosθ]² =
(sinθ/cosθ + cosθ/sinθ)² =
(tanθ + cotθ)²

<h3>Question 2</h3>

(1 - tan²θ) / (1 + tan²θ) =
(1 - sin²θ/cos²θ) / (1 + sin²θ/cos²θ) =
(cos²θ - sin²θ) / (cos²θ + sin²θ) =
(cosθ + sinθ)(cosθ - sinθ) / 1 =
(cosθ + sinθ)(cosθ - sinθ)

<h3>Question 3</h3>

sinθ/ (1 - cotθ) + cosθ / (1 - tanθ) =
sinθ / (1 - cosθ/sinθ) + cosθ / (1 - sinθ/cosθ) =
sinθ/ [(sinθ - cosθ) / sinθ] + cosθ / [(cosθ - sinθ)/cosθ] =
sin²θ/ (sinθ - cosθ) + cos²θ/(cosθ - sinθ) =
sin²θ/ (sinθ - cosθ) - cos²θ/(sinθ - cosθ) =
(sin²θ - cos²θ) / (sinθ - cosθ) =
(sinθ + cosθ)(sinθ - cosθ) / (sinθ - cosθ) =
sinθ + cosθ

6 0

3 years ago

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